问题
This is the data packet which was received from android mobile to my server.
$|351746051743568|12.9399604|77.6257631|0.0|1392979784822|1|#
In which following is the time which is received from the device: 1392979784822. Since this is in GPS format, I tried to convert into local format in SQL and failed. Please guide me in this issue.
回答1:
Looks like unix/epoch time in millisecs?
declare @x bigint = 1392979784822
declare @msin1day bigint = 3600 * 24 * 1000
select dateadd(ms, @x % @msin1day, dateadd(day, @x / @msin1day, '19700101'))
(No column name)
2014-02-21 10:49:44.823
来源:https://stackoverflow.com/questions/21936148/how-to-convert-time-which-is-in-gps-format-to-local-time-format-in-sql