问题
I am wondering how to get pure text form python email using imaplib. What i have so far:
from datetime import datetime
import imaplib ,email
IMAP_SERVER = 'imap.gmail.com'
EMAIL_ACCOUNT = "example@gmail.com"
PASSWORD = "password"
rv, data = M.search(None, "ALL")
if rv != 'OK':
print("No messages found!")
return
if data != ['']: # if not empty list means messages exist
for num in data[0].split():
rv, data = M.fetch(num, '(RFC822)') #(BODY[HEADER.FIELDS (SUBJECT FROM)])
if rv != 'OK':
print("ERROR getting message", num)
return
message = email.message_from_bytes(data[0][1])
text = ""
if message.is_multipart():
for payload in message.get_payload():
text = payload.get_payload()
else:
text = message.get_payload()
res = {
'From': email.utils.parseaddr(message['From'])[1],
'From name': email.utils.parseaddr(message['From'])[0],
'Time': datetime.fromtimestamp(email.utils.mktime_tz(email.utils.parsedate_tz(message['Date']))),
'To': message['To'],
'Subject': email.header.decode_header(message["Subject"])[0][0],
'Text': text
}
print(res['Text'])
else:
print("Nothing to work with.")
If i do it this way, the code works, but i get
<div dir="ltr">test 3 body</div>
as an output. Is there any way to get purely "test 3 body" out?
回答1:
If you just stack on removing html tags from string you have to use regular expression like here:
import re
s = '<div dir="ltr">test 3 body</div>'
print(re.sub('<[^<]+?>', '', s))
Output: test 3 body
s
has to be your res['Text']
.
回答2:
Look for the plain text part of the email message.
for payload in message.walk():
if payload.get_content_type().lower() == 'text/plain':
print(payload.get_payload())
来源:https://stackoverflow.com/questions/43586656/how-to-get-pure-text-from-python-email-using-imaplib