How can I compare two dates in PHP?

问题

In the database, the date looks like 2011-10-2.

If I wanted to compare today's date against the date in the database to see which one is greater, how would I do it?

I tried this,

$today = date("Y-m-d");
$expire = $row->expireDate //from db

if($today < $expireDate) { //do something; }

but it doesn't really work that way. What's another way of doing it?

Update: I know this post is kinda old but i just wanted to mention carbon, which is a class thats used with laravel but can be used with classic php and it does wonders with dates. check it out: Carbon

回答1:

in the database the date looks like this 2011-10-2

Store it in YYYY-MM-DD and then string comparison will work because '1' > '0', etc.

回答2:

If all your dates are posterior to the 1st of January of 1970, you could use something like:

$today = date("Y-m-d");
$expire = $row->expireDate; //from database

$today_time = strtotime($today);
$expire_time = strtotime($expire);

if ($expire_time < $today_time) { /* do Something */ }

If you are using PHP 5 >= 5.2.0, you could use the DateTime class:

$today_dt = new DateTime($today);
$expire_dt = new DateTime($expire);

if ($expire_dt < $today_dt) { /* Do something */ }

Or something along these lines.

回答3:

Just to compliment the already given answers, see the following example:

$today = new DateTime('');
$expireDate = new DateTime($row->expireDate); //from database



if($today->format("Y-m-d") < $expireDate->format("Y-m-d")) { 
    //do something; 
}

Update: Or simple use old-school date() function:

if(date('Y-m-d') < date('Y-m-d', strtotime($expire_date))){
    //echo not yet expired! 
}

回答4:

I would'nt do this with PHP. A database should know, what day is today.( use MySQL->NOW() for example ), so it will be very easy to compare within the Query and return the result, without any problems depending on the used Date-Types

SELECT IF(expireDate < NOW(),TRUE,FALSE) as isExpired FROM tableName

回答5:

$today = date('Y-m-d');//Y-m-d H:i:s
$expireDate = new DateTime($row->expireDate);// From db 
$date1=date_create($today);
$date2=date_create($expireDate->format('Y-m-d'));
$diff=date_diff($date1,$date2);

//echo $timeDiff;
if($diff->days >= 30){
    echo "Expired.";
}else{
    echo "Not expired.";
}

回答6:

$today_date=date("Y-m-d");
$entered_date=$_POST['date'];
$dateTimestamp1 = strtotime($today_date);
$dateTimestamp2 = strtotime($entered_date);
$diff= $dateTimestamp1-$dateTimestamp2;
//echo $diff;
if ($diff<=0)
   {
     echo "Enter a valid date";
   }

回答7:

Here's a way on how to get the difference between two dates in minutes.

// set dates
$date_compare1= date("d-m-Y h:i:s a", strtotime($date1));
// date now
$date_compare2= date("d-m-Y h:i:s a", strtotime($date2));

// calculate the difference
$difference = strtotime($date_compare1) - strtotime($date_compare2);
$difference_in_minutes = $difference / 60;

echo $difference_in_minutes;

回答8:

You can use simple PHP to compare dates:

$date = new simpleDate();
echo $date->now()->compare($expire_date)->isBeforeOrEqual();

This will give you true or false.

You can check the tutorials for more examples. Please click here.

回答9:

I had that problem too and I solve it by:

$today = date("Ymd");
$expire = str_replace('-', '', $row->expireDate); //from db

if(($today - $expire) > $NUMBER_OF_DAYS) 
{ 
    //do something; 
}

回答10:

Simply you can check..

if ($startdate < $date) {// do something} 
if ($startdate > $date) {// do something}

but both dates must be in same formatlike

Y-m-d or d-m-Y

etc.

回答11:

first of all, try to give the format you want to the current date time of your server:

Obtain current date time

$current_date = getdate();
Separate date and time to manage them as you wish:

$current_date_only = $current_date[year].'-'.$current_date[mon].'-'.$current_date[mday]; $current_time_only = $current_date['hours'].':'.$current_date['minutes'].':'.$current_date['seconds'];

Compare it depending if you are using donly date or datetime in your DB:

$today = $current_date_only.' '.$current_time_only;

or

$today = $current_date_only;

if($today < $expireDate)

hope it helps

回答12:

Here's my spin on how to get the difference in days between two dates with PHP. Note the use of '!' in the format to discard the time part of the dates, thanks to info from DateTime createFromFormat without time.

$today = DateTime::createFromFormat('!Y-m-d', date('Y-m-d'));
$wanted = DateTime::createFromFormat('!d-m-Y', $row["WANTED_DELIVERY_DATE"]);
$diff = $today->diff($wanted);
$days = $diff->days;
if (($diff->invert) != 0) $days = -1 * $days;
$overdue = (($days < 0) ? true : false);
print "<!-- (".(($days > 0) ? '+' : '').($days).") -->\n";

回答13:

Found the answer on a blog and it's as simple as:

strtotime(date("Y"."-01-01")) -strtotime($newdate))/86400

And you'll get the days between the 2 dates.

来源：https://stackoverflow.com/questions/59283366/nested-ifelse-error-on-values-between-a-given-range

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