问题
When I run the following servlet:
// package projectcodes;
public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException {
String UserID = request.getParameter("UserID");
String UserPassword = request.getParameter("UserPassword");
String userName = null;
String Email = null;
Encrypter encrypter = new Encrypter();
String hashedPassword = null;
try {
hashedPassword = encrypter.hashPassword(UserPassword);
Context context = new InitialContext();
DataSource ds = (DataSource)context.lookup("java:comp/env/jdbc/photog");
Connection connection = ds.getConnection();
String sqlStatement = "SELECT email,firstname FROM registrationinformation WHERE password='" + hashedPassword + "'";
PreparedStatement statement = connection.prepareStatement(sqlStatement);
ResultSet set = statement.executeQuery();
userName = set.getString(1); // <<---------- Line number 28
response.sendRedirect("portfolio_one.jsp");
// userName = set.getString("FirstName");
Email = set.getString(3);
if(set.wasNull() || Email.compareTo(UserID) != 0) {
// turn to the error page
response.sendRedirect("LoginFailure.jsp");
} else {
// start the session and take to his homepage
HttpSession session = request.getSession();
session.setAttribute("UserName", userName);
session.setMaxInactiveInterval(900); // If the request doesn't come withing 900 seconds the server will invalidate the session
RequestDispatcher rd = request.getRequestDispatcher("portfolio_one.jsp");
rd.forward(request, response); // forward to the user home-page
}
}catch(Exception exc) {
System.out.println(exc);
}
I get the following exceptions:
INFO: java.sql.SQLException: Invalid operation at current cursor position.
at org.apache.derby.client.am.SQLExceptionFactory40.getSQLException(Unknown Source)
at org.apache.derby.client.am.SqlException.getSQLException(Unknown Source)
at org.apache.derby.client.am.ResultSet.getString(Unknown Source)
at com.sun.gjc.spi.base.ResultSetWrapper.getString(ResultSetWrapper.java:155)
-----> at projectcodes.ValidateDataForSignIn.doPost(ValidateDataForSignIn.java:28
at javax.servlet.http.HttpServlet.service(HttpServlet.java:754)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:847)
at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1539)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:281)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175)
at org.apache.catalina.core.StandardPipeline.doInvoke(StandardPipeline.java:655)
at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:595)
at com.sun.enterprise.web.WebPipeline.invoke(WebPipeline.java:98)
at com.sun.enterprise.web.PESessionLockingStandardPipeline.invoke(PESessionLockingStandardPipeline.java:91)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:162)
at org.apache.catalina.connector.CoyoteAdapter.doService(CoyoteAdapter.java:330)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:231)
at com.sun.enterprise.v3.services.impl.ContainerMapper.service(ContainerMapper.java:174)
at com.sun.grizzly.http.ProcessorTask.invokeAdapter(ProcessorTask.java:828)
at com.sun.grizzly.http.ProcessorTask.doProcess(ProcessorTask.java:725)
at com.sun.grizzly.http.ProcessorTask.process(ProcessorTask.java:1019)
at com.sun.grizzly.http.DefaultProtocolFilter.execute(DefaultProtocolFilter.java:225)
at com.sun.grizzly.DefaultProtocolChain.executeProtocolFilter(DefaultProtocolChain.java:137)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:104)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:90)
at com.sun.grizzly.http.HttpProtocolChain.execute(HttpProtocolChain.java:79)
at com.sun.grizzly.ProtocolChainContextTask.doCall(ProtocolChainContextTask.java:54)
at com.sun.grizzly.SelectionKeyContextTask.call(SelectionKeyContextTask.java:59)
at com.sun.grizzly.ContextTask.run(ContextTask.java:71)
at com.sun.grizzly.util.AbstractThreadPool$Worker.doWork(AbstractThreadPool.java:532)
at com.sun.grizzly.util.AbstractThreadPool$Worker.run(AbstractThreadPool.java:513)
at java.lang.Thread.run(Thread.java:722)
Caused by: org.apache.derby.client.am.SqlException: Invalid operation at current cursor position.
at org.apache.derby.client.am.ResultSet.checkForValidCursorPosition(Unknown Source)
at org.apache.derby.client.am.ResultSet.checkGetterPreconditions(Unknown Source)
... 30 more
The logs above from the server show that line number 28 is the cause of the exception. But i am unable to get the reason for exception. All the columns in the table have a datatype of varchar.
I have highlighted line number 28 (cause of exception according to server logs) in the servlet code.
回答1:
You should use the next statement first.
ResultSet set = statement.executeQuery();
if (set.next()) {
userName = set.getString(1);
//your logic...
}
UPDATE
As the Java 6 Documentation says
A ResultSet cursor is initially positioned before the first row; the first call to the method next makes the first row the current row; the second call makes the second row the current row, and so on.
This means when you execute the sentence
ResultSet set = statement.executeQuery();
The ResultSet set will be created and pointing to a row before the first result of the data. You can look it this way:
SELECT email,firstname FROM registrationinformation
email | firstname
____________________________________
0 <= set points to here
1 email1@gmail.com | Email1 Person
2 foo@bar.com | Foo Bar
So, after openning your ResulSet, you execute the method next to move it to the first row.
if(set.next())
Now set looks like this.
email | firstname
____________________________________
0
1 email1@gmail.com | Email1 Person <= set points to here
2 foo@bar.com | Foo Bar
If you need to read all the data in the ResultSet, you should use a while instead of if:
while(set.next()) {
//read data from the actual row
//automatically will try to forward 1 row
}
If the set.next() return false, it means that there was no row to read, so your while loop will end.
More information here.
回答2:
ResultSet set = statement.executeQuery();
Iterate the set and then get String.
while(set.next()) {
me = set.getString(1); // <<---------- Line number 28
}
回答3:
You have to set the pointer to the correct position:
while(set.hasNext()){
set.next();
String a = set.getString(1);
String b = set.getString(2);
}
回答4:
after initializing ResultSet check if the cursor has row in it or not e.g.
if(rs.next()){
//your all other works should go here
}
回答5:
You can get the first with: rs.first()
来源：https://stackoverflow.com/questions/10298794/resultset-getstring1-throws-java-sql-sqlexception-invalid-operation-at-curren