问题
With Reference to this question on android stack, i have a solution to do which allows android phone to provide support for setting non-english language password.
My phones SRC is based on stock-android which is not allowing me to set password which is non-ascii standards like Hebrew.
Based from AOSP source code that handles the password input for lock screen, ChooseLockPassword.java, inside validatePassword() (line 292), here is a snippet that will show the "illegal character" message (from line 311):
// allow non control Latin-1 characters only
if (c < 32 || c > 127) {
return getString(R.string.lockpassword_illegal_character);
}
I have commented out this part but i don't think so this will work. [Waiting to be Flashed] There are no such question for this condition, i need help for cracking the possibility for doing this any "Work around" will also do.
回答1:
So after fighting few days i got a workaround by implementing my method for it.
private String validateHebrewPassword(String password)
{
if (password.length() < mPasswordMinLength) {
return getString(mIsAlphaMode ?
R.string.lockpassword_password_too_short
: R.string.lockpassword_pin_too_short, mPasswordMinLength);
}
if (password.length() > mPasswordMaxLength) {
return getString(mIsAlphaMode ?
R.string.lockpassword_password_too_long
: R.string.lockpassword_pin_too_long, mPasswordMaxLength + 1);
}
for (int i = 0; i < password.length(); i++)
{
char c = password.charAt(i);
System.out.println("Validate Hebrew Password Success "+ " Char "+c+" for password "+password+ " langauage "+locale);
}
return null;
}
And modiying its validatePasswor() caller a bit specific to hebrew like:
private void handleNext() {
final String pin = mPasswordEntry.getText().toString();
if (TextUtils.isEmpty(pin)) {
return;
}
String errorMsg = null;
if (mUiStage == Stage.Introduction)
{
String locale = java.util.Locale.getDefault().getLanguage();
if(locale.equals("iw")) //Specific Hebrew check
{
errorMsg = validateHebrewPassword(pin); //New Method
}
else
{
errorMsg = validatePassword(pin); //AOSP Method
}
if (errorMsg == null)
{
mFirstPin = pin;
mPasswordEntry.setText("");
updateStage(Stage.NeedToConfirm);
}
} else if (mUiStage == Stage.NeedToConfirm) {
if (mFirstPin.equals(pin)) {
final boolean isFallback = getActivity().getIntent().getBooleanExtra(
LockPatternUtils.LOCKSCREEN_BIOMETRIC_WEAK_FALLBACK, false);
mLockPatternUtils.clearLock(isFallback);
mLockPatternUtils.saveLockPassword(pin, mRequestedQuality, isFallback);
getActivity().setResult(RESULT_FINISHED);
getActivity().finish();
} else {
CharSequence tmp = mPasswordEntry.getText();
if (tmp != null) {
Selection.setSelection((Spannable) tmp, 0, tmp.length());
}
updateStage(Stage.ConfirmWrong);
}
}
if (errorMsg != null) {
showError(errorMsg, mUiStage);
}
}
private void updateUi() {
String password = mPasswordEntry.getText().toString();
final int length = password.length();
if (mUiStage == Stage.Introduction && length > 0) {
if (length < mPasswordMinLength) {
String msg = getString(mIsAlphaMode ? R.string.lockpassword_password_too_short
: R.string.lockpassword_pin_too_short, mPasswordMinLength);
mHeaderText.setText(msg);
mNextButton.setEnabled(false);
} else
{
String locale = java.util.Locale.getDefault().getLanguage();
String error = null;
if(locale.equals("iw")) //Specific Hebrew check
{
error = validateHebrewPassword(password); //New method
}
else
{
error = validatePassword(password); //AOSP Method
}
if (error != null) {
mHeaderText.setText(error);
mNextButton.setEnabled(false);
} else {
mHeaderText.setText(R.string.lockpassword_press_continue);
mNextButton.setEnabled(true);
}
}
} else {
mHeaderText.setText(mIsAlphaMode ? mUiStage.alphaHint : mUiStage.numericHint);
mNextButton.setEnabled(length > 0);
}
mNextButton.setText(mUiStage.buttonText);
}
来源:https://stackoverflow.com/questions/27182362/settings-non-english-language-password-on-android-phone