问题
I had this code working fine with EclipseLink 2.5.2, but moving to 2.6.0 breaks the XmlValue
annotation:
The property or field value cannot be annotated with XmlValue since it is a subclass of another XML-bound class.
Base class look like this:
public abstract class Baseclass {
@XmlAttribute
private String baseValue;
// ...
}
One of two subclasses (composite pattern, class B can have a list of BaseClass elements):
@XmlRootElement(name = "A")
public class A extends BaseClass {
@XmlValue
private String aValue;
}
And the usage:
public class Root {
@XmlElements({
@XmlElement(class = A.class),
@XmlElement(class = B.class)
})
private BaseClass object;
}
Unfortunately the class layout can't be changed, because it's JPA persisted to a database. I tried to wrap the A and B classes with an XmlJavaTypeAdapter
without success.
Is it possible to use the annotation in the way as before with EL 2.6 or through an adapter class?
回答1:
I managed to solve the issue using a XmlAdapter.
In the subclass replace the XmlValue annotation:
@XmlPath(".")
@XmlJavaTypeAdapter(AClassAdapter.class)
private String aValue;
And the adapter implementation:
public class AClassAdapter extends XmlAdapter<AdaptedValue, String> {
public static class AdaptedValue {
@XmlValue
public String value;
public AdaptedValue() {
}
public AdaptedValue(String value) {
this.value = value;
}
}
@Override
public String unmarshal(AdaptedValue v) throws Exception {
return v.value;
}
@Override
public AdaptedValue marshal(String v) throws Exception {
return new AdaptedValue(v);
}
}
The XmlPath(".")
did the trick. Without it, the marshalled XML still has the value of aValue
wrapped in <aValue>
nodes.
来源:https://stackoverflow.com/questions/32625797/make-use-of-xmlvalue-in-subclass