问题
I have tried creating the following function:
def 3utr():
do_something().
However, I get a SyntaxError. Replacing the "3" by "three" fixes the problem.
My questions are:
- Why is it a syntax error?
- Is there a way to have a function name start with a number in Python 3?
回答1:
It is a syntax error because the language specification does not allow identifiers to start with a digit. So it’s not possible to have function names (which are identifiers) that start with digits in Python.
identifier ::= (letter|"_") (letter | digit | "_")*
Python 2 Language Reference
Within the ASCII range (U+0001..U+007F), the valid characters for identifiers are the same as in Python 2.x: the uppercase and lowercase letters A through Z, the underscore _ and, except for the first character, the digits 0 through 9.
Python 3 Language Reference
来源：https://stackoverflow.com/questions/13755532/defining-a-function-name-that-starts-with-a-number-in-python-3