问题
I have made a class with name of Movie with folowing fields:
@Id
@GeneratedValue
private Long id;
private String name;
@ElementCollection(targetClass = String.class)
private Map<String, String> properties;
private Double rate;
private Integer votersCount;
private Date releaseDate;
private Integer runtime;
@ManyToMany
@JoinTable(name = "movie_director")
@IndexColumn(name = "directorIndex")
private List<Person> directors;
@ManyToMany
@JoinTable(name = "movie_writer")
@IndexColumn(name = "writerIndex")
private List<Person> writers;
@OneToMany
@IndexColumn(name = "roleIndex")
private List<MovieRole> movieRoles;
@ManyToMany
@JoinTable(name = "movie_genre")
@IndexColumn(name = "genreIndex")
private List<Genre> genres;
as you can see, I have used hibernate annotation and object is bean. but when I try to open my hibernate session with the following code...
session = HibernateSessionFactory.getSessionFactory().openSession();
I encounter a problem regarding could not map a Java.Util.Map class. Here is exception stack trace:
org.hibernate.MappingException: Could not determine type for: java.util.Map, for columns: [org.hibernate.mapping.Column(properties)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:266)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:253)
at org.hibernate.mapping.Property.isValid(Property.java:185)
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:410)
at org.hibernate.mapping.RootClass.validate(RootClass.java:192)
at org.hibernate.cfg.Configuration.validate(Configuration.java:1099)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1284)
at main.HibernateSessionFactory.getSessionFactory(HibernateSessionFactory.java:29)
at main.MainClass.main(MainClass.java:26)
I'm new to hibernate and don't know exactly what's happening... please help me!
回答1:
that's because you have to use some jpa2 implementation! this guy had the same problem
回答2:
I also face the same problem.It is late but i think it will help others.use @MapKeyColumn.here is my simple code
@ElementCollection(targetClass=String.class)
@MapKeyColumn(name="Employee_Position")
private Map<String,String> position=new HashMap<String,String>();
回答3:
Shouldn't properties just be a List<String>
type?
It sounds like Hibernates confusion is the same as mine which is, why is Properies a Map instead of a list? What exactly are you trying to do there?
回答4:
Aah I see, its a . I dont think you can map a primitive unless you are using latest jar. https://forum.hibernate.org/viewtopic.php?t=955308. Check that link. Could you make a class called as Properties with key and value and then use it? I had a similar problem and I had to use that approach.
回答5:
Do you have both getter and setter for Properties?
来源:https://stackoverflow.com/questions/4324839/java-hibernate-mapping-exception-could-not-determine-type-for-java-util-map