Preg_replace and preg_match to get and replace HTML / PHP content

问题

I need to extract some HTML / PHP content and put it into an array.

Here is what I have

The code below is within a string called $string for example.

<html>
<?php myclass->my_function('First', 'Last'); ?>
<p>Some other content</p>
<?php myclass->my_function(1, 2, 3); ?>
</html>

I want to find all the values from the functions and sum them into an array with preg_match. Only myclass->my_function function values should be found.

The array should look like this

$array = array(
   1 => array('First', 'Last'),
   2 => array(1,2,3),
);

Then I want preg_replace to replace all the rows with [explode_id] and the result should be:

<html>
[explode_1]
<p>Some other content</p>
[explode_2]
</html>

Thanks!

回答1:

$str = '<html>
<?php myclass->my_function(\'styles\', \'home.css\'); ?>
<p>Some other content</p>
<?php myclass->my_function(1, 2, 3); ?>
</html>';

function jens($matches)
{ 
    $path = '';
    $parts = explode(',', $matches[1]);
    foreach($parts as $match)
        $path .= '/' . str_replace('\'', '', trim($match));

    return $path;
}

$replaced = preg_replace_callback('/<\?php myclass->my_function\((.*?)\); \?>/', 'jens', $str);

echo $replaced;

Should do what you want.

回答2:

$match_array = preg_match('/<\?php myclass->my_function\((.+?)\); \?>/', $input_string, $matches);
$output_arrays = array();
$output_arrays[] = eval('array('.$matches[0][1].')';
$output_arrays[] = eval('array('.$matches[1][1].')';

echo '<html>';
echo implode(' ', $output_arrays[0]);
echo '<p>Some other content</p>';
echo implode(' ', $output_arrays[1]);
echo '</html>';

来源：https://stackoverflow.com/questions/4727191/preg-replace-and-preg-match-to-get-and-replace-html-php-content

标签

php

arrays

preg-replace

preg-match