问题
i created a fake console navigation for my site where people would have to enter a specific value or 'command' to show the div that it corresponds to. i got this to work for one div but i'm wondering how i can get it to work with multiple divs. when i tried this jquery script the divs show up fine independently, but if i try searching for one after the other, #div2 shows up on the left of #div1 and does some weird flickering, or #div1 refuses to disappear.
var div = $('#div1').hide();
$('input').keydown(function() {
var value = this.value;
if ($('input').val() == 'div1') {
$('#div1').slideDown();
} else {
div.hide();
}
});
var div = $('#div2').hide();
$('input').keydown(function() {
var value = this.value;
if ($('input').val() == 'div2') {
$('#div2').slideDown();
} else {
div.hide();
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script>
<input type="text" placeholder="ENTER 'div1' or 'div2' COMMAND" />
<div id="div1">div1 content</div>
<div id="div2">div2 content</div>
i want the divs to disappear when you backspace and enter in the input entry field, and i want the current div to disappear when you enter a new command. so what do i need to change? do the divs need to go in wrapper?
回答1:
Try this snippet!
// Hide both <div> by default
$('#div1').hide();
$('#div2').hide();
// Check on keydown
$('input').keydown(function() {
if ($('input').val() == 'div1') { // If input value is div1
$('#div2').hide();
$('#div1').slideDown();
} else if ($('input').val() == 'div2') { // If input value is div2
$('#div1').hide();
$('#div2').slideDown();
} else { // If input value is not equal to div1 or div2, hide both
$('#div1').hide();
$('#div2').hide();
}
});
You can also have a common CSS
class like .hide
with display: none;
property to initially hide the <div>
.
Hope it helps!
回答2:
Try to add one common Class for all div and show/hide using the name of class
search for all this class divs and hide them
for exmaple
HTML
<div id="div1" class="CommonClass">div1 content</div>
<div id="div2" class="CommonClass">div2 content</div>
JS
$(".CommonClass").each(function(index,obj)){
$(obj).hide(); // Or $(obj).css("display","none")
}
回答3:
Ok you can simplify it by and use .keyup()
instead of .keydown()
$('div[id^=div]').hide();
$('input').keyup(function() {
var id = $.trim($(this).val().toLowerCase());
$('div[id^=div]').hide();
$('#'+id).slideDown();
});
DEMO
来源:https://stackoverflow.com/questions/34110766/how-to-show-hide-multiple-divs-based-on-input-value