问题
I'm making a JOptionpane where the user can has to enter hes name. So it can't be empty and it can't be a number
The empty part is working but now I have to find a solution for the number part
As you can see in my code I made a while loop to check if "naam" isn't empty. Now I need to find a way to check if "naam" isn't a number.
String naam = JOptionPane.showInputDialog("Geef uw naam in: ");
while (naam.equals("")) {
JOptionPane.showMessageDialog(null, "Geef een naam in", "Geef naam", JOptionPane.ERROR_MESSAGE);
naam = JOptionPane.showInputDialog("Geef uw naam in: ");
回答1:
You can use regex to check if it contains any digits. The regex "\\D" in java stands for a non-digit, and "+" stands for 1 or more. So you can change your while loop to:
while (!naam.matches("\\D+"))
This will include the empty equals check, as you need to have at least one non-digit for it to match.
回答2:
You could simply filter the input directly at the dialog, instead of messing about having to display error dialogs and re-showing the dialog...
import java.awt.EventQueue;
import javax.swing.JOptionPane;
import javax.swing.JTextField;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
import javax.swing.text.AbstractDocument;
import javax.swing.text.AttributeSet;
import javax.swing.text.BadLocationException;
import javax.swing.text.DocumentFilter;
public class TestOptionPane08 {
public static void main(String[] args) {
new TestOptionPane08();
}
public TestOptionPane08() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
}
JTextField name = new JTextField(10);
((AbstractDocument) name.getDocument()).setDocumentFilter(new DocumentFilter() {
public String filter(String text) {
StringBuilder sb = new StringBuilder(text.length());
for (char c : text.toCharArray()) {
if (!Character.isDigit(c)) {
sb.append(c);
}
}
return sb.toString();
}
@Override
public void insertString(DocumentFilter.FilterBypass fb, int offset, String string, AttributeSet attr) throws BadLocationException {
super.insertString(fb, offset, filter(string), attr);
}
@Override
public void replace(DocumentFilter.FilterBypass fb, int offset, int length, String text, AttributeSet attrs) throws BadLocationException {
String filter = filter(text);
super.replace(fb, offset, length, filter, attrs);
}
});
JOptionPane.showMessageDialog(null, name, "Name Please", JOptionPane.QUESTION_MESSAGE);
}
});
}
}
Now, you could add the JTextField
to JPanel
and add a JLabel
as well and even error messages...
回答3:
Use regular expressions.
if (naam.matches("\\d+")) {/*it is a number*/}
String.matches(regexp) returns true
if the string matches the regular expression given as parameter. In this example, \\d+
matches one or more digits.
You may try other patterns in order to disallow strings with invalid characters (such as "My#name
") but that depends on your definition of "name character".
For instance [A-Z][a-z]*(?:\\s[A-Z][a-z]*)
matches strings with one or more sequences of an uppercase character followed by zero-or-more lowercase characters, each sequence separated by a single space, such as My Name Is X
.
来源:https://stackoverflow.com/questions/15284062/input-can-only-be-string