A for loop for multiple likert graphs returns NOTHING

问题

I set up a large amount of likert and other graphs to evaluate the total results of my questionnaire.

Now I would like to do the same thing by a grouping variable "group"

I set up all of my likert items and their definitions (my data is in a god-awful format, so I had to reformat it with R). The idea for the code is the following: 1. group and rename the questions according to the likert () functions needs 2. have R split the dataframe according to 11 groups 3. plot a likert graph for each of these groups

Now this should be the solution (it worked for the barplots but for some reason is not working for the likert plots):

for(i in 1:11)
{
x<-F5[which(F5$group==i),]
plot(likert(x[1:9]),low.color="red3", high.color="forestgreen",
 include.center=T, plot.percents=T,ordered=T, 
 legend= paste("F5","Gruppe",i), 
 legend.position="bottom",
 plot.percent.low=F,plot.percent.high=F)+ylab(ylab)+ggtitle(title.F5)
}

when I run this code exactly NOTHING happens. No likert graphs are plotted, no error messages etc.

EXAMPLE DATA so everyone can join the fun:

 M1 M2 M3 M4 M5 M6 M7 M8 M9 group
1   1  5  5  1  2  4  4 -9  5     1
2   2  4  5  1  2  4  4  1  5     1
3   3  3  5  1  2  4  3  1  3     1
4   1  5  5  1  2  4  4 -9  5     1
5   2  4  5  1  2  4  4  1  5     2
6   1  5  5  1  2  4  4 -9  5     2
7   2  4  5  1  2  4  4  1  5     2
8   3  3  5  1  2  4  3  1  3     3
9   4  5  5  1  2  4 -9  1  3     3
10  5  5 -9  1  3  4  4  2 -9     3
11  3  3  5  1  2  4  3  1  3     3
12  4  5  5  1  2  4 -9  1  3     4
13  5  5 -9  1  3  4  4  2 -9     3
14  5  5 -9  1  3  4  4  2 -9     3
15  3  3  5  1  2  4  3  1  3     4
16  1  5  5  1  2  4  4 -9  5     4
17  2  4  5  1  2  4  4  1  5     4
18  1  5  5  1  2  4  4 -9  5     4
19  2  4  5  1  2  4  4  1  5     4
20  3  3  5  1  2  4  3  1  3     4

Change data from numeric to likert-style items of agreement

DATA[,1:9][DATA[,1:9]==1]<-"strongly agree"
DATA[,1:9][DATA[,1:9]==2]<-"agree"
DATA[,1:9][DATA[,1:9]==3]<-"unsure"
DATA[,1:9][DATA[,1:9]==4]<-"disagree"
DATA[,1:9][DATA[,1:9]==5]<-"strongly disagree"
DATA[,1:9][DATA[,1:9]==-9]<-NA

Set agreement scale

agr<-c("stronlgy agree", "agree", "unsure", "disagree", "strongly disagree")

Define each as ordered factors to the previously defined scale

DATA[,1]=factor(DATA[,1], levels=agr, ordered=TRUE)
DATA[,2]=factor(DATA[,2], levels=agr, ordered=TRUE)
DATA[,3]=factor(DATA[,3], levels=agr, ordered=TRUE)
DATA[,4]=factor(DATA[,4], levels=agr, ordered=TRUE)
DATA[,5]=factor(DATA[,5], levels=agr, ordered=TRUE)
DATA[,6]=factor(DATA[,6], levels=agr, ordered=TRUE)
DATA[,7]=factor(DATA[,7], levels=agr, ordered=TRUE)
DATA[,8]=factor(DATA[,8], levels=agr, ordered=TRUE)
DATA[,9]=factor(DATA[,9], levels=agr, ordered=TRUE)

set title to sth funny

title.DATA<-"This message will not show up because R is stupid."
program a loop and watch R do NOTHING

for(i in 1:11) { x<-DATA[which(DATA$group==i),] plot(likert(x[1:9]),low.color="red3", high.color="forestgreen", include.center=T, plot.percents=T,ordered=T, legend= paste("DATA","Gruppe",i), legend.position="bottom", plot.percent.low=F,plot.percent.high=F)+ylab(ylab)+ggtitle(title.DATA) }

回答1:

It works for me like that. I came across this problem myself recently. graphics plots print automatically in loops, grid plots don't. For them you have to add print.


library(likert)

for(i in 1:4) { x<-DATA[which(DATA$group==i),] 
lp <- plot(likert(x[1:9]),low.color="red3", 
high.color="forestgreen", include.center=T, 
plot.percents=T,ordered=T, legend= paste("DATA","Gruppe", i), 
legend.position="bottom", plot.percent.low=F,plot.percent.high=F) +
  ylab("ylab") +
  ggtitle("This message will not show up because R is stupid.")

print(lp)
}

来源：https://stackoverflow.com/questions/55650737/a-for-loop-for-multiple-likert-graphs-returns-nothing

标签

likert