Get last day of previous month in yyyy-mm-dd format

问题

How do I get the last day of the previous month in yyyy-mm-dd format?

This is what I have tried, however I don't want the seconds showing. Only YYYY-MM-DD:

SELECT DATEADD(s, -1, DATEADD(mm, DATEDIFF(m, 0, GETDATE()), 0))

回答1:

Use the EOMONTH function along with FORMAT:

SELECT FORMAT(EOMONTH(CURRENT_TIMESTAMP, -1), 'yyyy-MM-dd')

The -1 in the above example means subtract 1 month from argument 1 (there is no need for DATEADD).

回答2:

Convert it into date only format

SELECT convert(date,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)),103)

回答3:

this should work

 SELECT CONVERT(VARCHAR(10),  DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)), 120)  

回答4:

Try this which is popular :

 SELECT CONVERT(VARCHAR(10),DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)),120)  

Live demo

回答5:

try this:

Select CONVERT(varchar, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)),23)

回答6:

I would use this, due to newer versions of SQL supporting it:

SELECT  CONVERT(DATE,EOMONTH(DATEADD(MM,-1,GETDATE())),103)

Code is shorter to accomplish the same task...

来源：https://stackoverflow.com/questions/57674607/get-last-day-of-previous-month-in-yyyy-mm-dd-format