Multi-armed bandits with Rcpp

泪湿孤枕 提交于 2020-01-06 07:07:38

问题


I am translating the epsilon-greedy algorithm for multiarmed bandits from here. This is a rather nice demonstration of the power and elegance of Rcpp. However, the results from this version do not tally with the one that is mentioned in the link above. I am aware that this is probably a very niche question but have no other venue to post this on!

A summary of the code is as follows. Basically, we have a set of arms, each of which pays out a reward with a pre-defined probability and our job is to show that by drawing at random from the arms while drawing the arm with the best reward intermittently eventually allows us to converge on to the best arm. A nice explanation of this algorithm is provided by John Myles White.

Now, to the code:

#include <Rcpp.h>

using namespace Rcpp;

// [[Rcpp::depends(RcppArmadillo)]]
// [[Rcpp::plugins(cpp11)]]

struct EpsilonGreedy {
  double epsilon;
  std::vector<int> counts;
  std::vector<double> values;
};

int index_max(std::vector<double>& v) {
  return std::distance(v.begin(), std::max_element(v.begin(), v.end()));
}

int index_rand(std::vector<double>& v) {
  return R::runif(0, v.size()-1);
}

int select_arm(EpsilonGreedy& algo) {
  if (R::runif(0, 1) > algo.epsilon) {
    return index_max(algo.values);
  } else {
    return index_rand(algo.values);
  }
}

void update(EpsilonGreedy& algo, int chosen_arm, double reward) {
  algo.counts[chosen_arm] += 1;

  int n = algo.counts[chosen_arm];
  double value = algo.values[chosen_arm];

  algo.values[chosen_arm] = ((n-1)/n) * value + (1/n) * reward;
}

struct BernoulliArm {
  double p;
};

int draw(BernoulliArm arm) {
  if (R::runif(0, 1) > arm.p) {
    return 0;
  } else {
    return 1;
  }
}

// [[Rcpp::export]]
DataFrame test_algorithm(double epsilon, std::vector<double>& means, int n_sims, int horizon) {

  std::vector<BernoulliArm> arms;

  for (auto& mu : means) {
    BernoulliArm b = {mu};
    arms.push_back(b);
  }

  std::vector<int> sim_num, time, chosen_arms;
  std::vector<double> rewards;

  for (int sim = 1; sim <= n_sims; ++sim) {

    std::vector<int> counts(means.size(), 0);
    std::vector<double> values(means.size(), 0.0); 

    EpsilonGreedy algo = {epsilon, counts, values};

    for (int t = 1; t <= horizon; ++t) {
      int chosen_arm = select_arm(algo);
      double reward = draw(arms[chosen_arm]);
      update(algo, chosen_arm, reward);

      sim_num.push_back(sim);
      time.push_back(t);
      chosen_arms.push_back(chosen_arm);
      rewards.push_back(reward);
    }
  }

  DataFrame results = DataFrame::create(Named("sim_num") = sim_num,
                                        Named("time") = time,
                                        Named("chosen_arm") = chosen_arms,
                                        Named("reward") = rewards);

  return results;
}

/***R

means <- c(0.1, 0.1, 0.1, 0.1, 0.9)
results <- test_algorithm(0.1, means, 5000, 250) 

p2 <- ggplot(results) + geom_bar(aes(x = chosen_arm)) + theme_bw()
*/

The plot of the arm chosen during simulations (i.e., plot p2 above) is as follows:

Obviously, the first arm is being chosen disproportionately despite having a low reward! What is going on?


回答1:


I don't know how the bandits are supposed to work, but a little standard debugging (ie: look at the values generated) revealed that you generated lots of zeros.

After fixing some elementary errors (make your C/C++ loops for (i=0; i<N; ++) ie start at zero and compare with less-than) we are left with other less subtle errors such as runif(1,N) cast to int not giving you a equal range over N values (hint: add 0.5 and round and cast, or sample one integer from the set of 1..N integers).

But the main culprit seems to be your first argument epsilon. Simply setting that to 0.9 gets me a chart like the following where you still the issue with the last 'half' unit missing.



来源:https://stackoverflow.com/questions/49629277/multi-armed-bandits-with-rcpp

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