Get complete ddl for index in oracle

问题

I am using oracle 11g/12c. I want to get ddl of indexes in my database. For this I used the query -

SELECT DBMS_METADATA.GET_DDL('INDEX','SYS_IL0000091971C00001$$','CCEEXPERTS') FROM dual

Here 'SYS_IL0000091971C00001$$' is my index name and 'CCEEXPERTS' is my owner name.

From this I get the ddl -

 CREATE UNIQUE INDEX "CCEEXPERTS"."SYS_IL0000091971C00001$$" ON "CCEEXPERTS"."DATABLOB" (

And my actual ddl is -

CREATE UNIQUE INDEX "CCEEXPERTS"."SYS_IL0000091971C00001$$" ON "CCEEXPERTS"."DATABLOB" (
  PCTFREE 10 INITRANS 2 MAXTRANS 255 
  STORAGE(INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
  PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1
  BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
  TABLESPACE "USERS" 
  PARALLEL (DEGREE 0 INSTANCES 0) ;

In actual ddl after "CCEEXPERTS"."DATABLOB" ( , next line character and from their the ddl is truncted.

How can I get the complete ddl? Please help me...

Thanks in advance.

回答1:

In SQLplus, set these before running the procedure.

set long 100000
set longchucksize 100000

来源：https://stackoverflow.com/questions/42152677/get-complete-ddl-for-index-in-oracle