问题
I have a C# application and I use type to insert into a SQL Server table:
CREATE TYPE [dbo].[taradodType] AS TABLE
(
[IDP] [int] NULL,
[date] [datetime] NULL,
[day] [nvarchar](max) NULL,
[nobatkari] [nvarchar](max) NULL,
[code] [nvarchar](max) NULL
)
C# code :
SqlConnection sqlconn = new SqlConnection(DBsetting.Connstring);
sqlconn.Open();
using (sqlconn)
{
try
{
SqlCommand cmd = new SqlCommand("InsertTaradod", sqlconn);
cmd.CommandType = CommandType.StoredProcedure;
SqlParameter dtparam = cmd.Parameters.AddWithValue("@taradodType", dtreadd);
dtparam.SqlDbType = SqlDbType.Structured;
cmd.ExecuteNonQuery();
MessageBox.Show("Saved!");
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
Stored procedure:
ALTER PROCEDURE [dbo].[InsertTaradod]
@taradodType dbo.taradodType READONLY
AS
BEGIN
INSERT INTO dbo.taradod
SELECT * FROM @taradodType
END
And I don't want to insert duplicate rows into the table. So I defined an index not to insert duplicate data. But there is a problem here. If there is only 1 duplicated row in data collection. None of the data is inserted, but I want to insert other data which is not duplicated
Data :
1 2017-06-20 13:28:44 1 0 1 0
4 2017-06-22 12:18:13 1 0 1 0
2 2017-06-22 12:49:41 1 0 1 0
3 2017-06-22 13:15:24 1 0 1 0
1 2017-06-22 13:50:07 1 0 1 0
3 2017-06-24 06:56:05 1 0 1 0
1 2017-06-24 07:02:47 1 0 1 0
5 2017-06-24 07:29:37 1 0 1 0
7 2017-06-24 13:18:57 1 0 1 0
6 2017-06-24 13:19:00 1 0 1 0
8 2017-06-24 13:19:03 1 0 1 0
5 2017-06-24 13:19:07 1 0 1 0
3 2017-06-24 14:35:14 1 0 1 0
1 2017-06-24 14:38:04 1 0 1 0
3 2017-06-25 06:45:24 1 0 1 0
2 2017-06-25 06:54:48 1 0 1 0
1 2017-06-25 06:56:02 1 0 1 0
5 2017-06-25 07:51:32 1 0 1 0
6 2017-06-25 07:57:25 1 0 1 0
7 2017-06-25 07:57:30 1 0 1 0
8 2017-06-25 07:57:34 1 0 1 0
2 2017-06-25 13:03:55 1 0 1 0
5 2017-06-25 13:26:34 1 0 1 0
6 2017-06-25 13:32:56 1 0 1 0
8 2017-06-25 13:33:07 1 0 1 0
7 2017-06-25 13:33:10 1 0 1 0
1 2017-06-25 14:38:51 1 0 1 0
3 2017-06-25 14:39:21 1 0 1 0
4 2017-06-28 06:44:48 1 0 1 0
3 2017-06-28 06:45:48 1 0 1 0
1 2017-06-28 06:59:51 1 0 1 0
5 2017-06-28 07:21:28 1 0 1 0
9 2017-06-28 07:38:38 1 0 1 0
8 2017-06-28 07:49:19 1 0 1 0
6 2017-06-28 08:11:29 1 0 1 0
7 2017-06-28 08:11:34 1 0 1 0
8 2017-06-28 13:32:17 1 0 1 0
9 2017-06-28 13:32:20 1 0 1 0
7 2017-06-28 13:32:23 1 0 1 0
6 2017-06-28 13:32:27 1 0 1 0
5 2017-06-28 13:32:42 1 0 1 0
4 2017-06-28 14:17:00 1 0 1 0
3 2017-06-28 14:43:18 1 0 1 0
1 2017-06-28 15:27:57 1 0 1 0
4 2017-06-29 06:28:16 1 0 1 0
1 2017-06-29 06:55:45 1 0 1 0
3 2017-06-29 06:55:53 1 0 1 0
5 2017-06-29 07:34:44 1 0 1 0
8 2017-06-29 07:55:54 1 0 1 0
6 2017-06-29 07:55:57 1 0 1 0
9 2017-06-29 07:56:01 1 0 1 0
7 2017-06-29 08:00:26 1 0 1 0
9 2017-06-29 12:57:04 1 0 1 0
7 2017-06-29 12:57:12 1 0 1 0
8 2017-06-29 12:57:15 1 0 1 0
6 2017-06-29 12:57:33 1 0 1 0
5 2017-06-29 12:57:54 1 0 1 0
4 2017-06-29 13:01:06 1 0 1 0
3 2017-06-29 13:31:41 1 0 1 0
1 2017-06-29 13:31:50 1 0 1 0
4 2017-07-01 06:27:33 1 0 1 0
2 2017-07-01 06:50:55 1 0 1 0
3 2017-07-01 06:51:52 1 0 1 0
1 2017-07-01 07:02:29 1 0 1 0
5 2017-07-01 07:18:49 1 0 1 0
9 2017-07-01 07:27:00 1 0 1 0
8 2017-07-01 07:27:03 1 0 1 0
7 2017-07-01 07:52:45 1 0 1 0
6 2017-07-01 07:52:47 1 0 1 0
2 2017-07-01 12:54:23 1 0 1 0
7 2017-07-01 13:32:05 1 0 1 0
8 2017-07-01 13:32:15 1 0 1 0
9 2017-07-01 13:32:37 1 0 1 0
6 2017-07-01 13:32:52 1 0 1 0
4 2017-07-01 13:32:58 1 0 1 0
5 2017-07-01 13:33:07 1 0 1 0
1 2017-07-01 14:32:01 1 0 1 0
3 2017-07-01 14:32:32 1 0 1 0
4 2017-07-02 06:27:25 1 0 1 0
3 2017-07-02 06:47:46 1 0 1 0
1 2017-07-02 07:00:37 1 0 1 0
2 2017-07-02 07:00:42 1 0 1 0
5 2017-07-02 07:11:05 1 0 1 0
8 2017-07-02 07:23:47 1 0 1 0
9 2017-07-02 07:23:55 1 0 1 0
7 2017-07-02 07:34:37 1 0 1 0
6 2017-07-02 07:34:39 1 0 1 0
2 2017-07-02 13:00:14 1 0 1 0
8 2017-07-02 13:22:30 1 0 1 0
9 2017-07-02 13:22:34 1 0 1 0
6 2017-07-02 13:23:09 1 0 1 0
7 2017-07-02 13:23:23 1 0 1 0
5 2017-07-02 13:26:15 1 0 1 0
4 2017-07-02 14:05:00 1 0 1 0
3 2017-07-02 14:56:15 1 0 1 0
1 2017-07-02 15:27:23 1 0 1 0
4 2017-07-03 06:33:45 1 0 1 0
1 2017-07-03 07:04:39 1 0 1 0
5 2017-07-03 07:15:34 1 0 1 0
6 2017-07-03 08:37:04 1 0 1 0
7 2017-07-03 08:37:07 1 0 1 0
8 2017-07-03 09:59:10 1 0 1 0
9 2017-07-03 09:59:14 1 0 1 0
8 2017-07-03 13:59:10 1 0 1 0
9 2017-07-03 13:59:25 1 0 1 0
5 2017-07-03 13:59:33 1 0 1 0
7 2017-07-03 13:59:42 1 0 1 0
6 2017-07-03 13:59:46 1 0 1 0
4 2017-07-03 14:05:22 1 0 1 0
1 2017-07-03 14:35:43 1 0 1 0
4 2017-07-04 06:28:15 1 0 1 0
2 2017-07-04 06:46:19 1 0 1 0
1 2017-07-04 07:06:26 1 0 1 0
3 2017-07-04 07:10:29 1 0 1 0
5 2017-07-04 07:18:38 1 0 1 0
8 2017-07-04 07:55:10 1 0 1 0
9 2017-07-04 07:55:14 1 0 1 0
1 2017-07-04 07:55:42 1 0 1 0
7 2017-07-04 07:57:51 1 0 1 0
6 2017-07-04 07:57:54 1 0 1 0
1 2017-07-04 08:57:36 1 0 1 0
Index is on ID
and datetime
.
回答1:
Your insert command is executing like a batch.
Your entire type is passed to the SQL Server stored procedure and it executes as a batch to insert.
In your stored procedure's INSERT
statement, add a NOT EXISTS
check like this:
INSERT INTO dbo.taradod
SELECT Distinct *
FROM @taradodType a
WHERE NOT EXISTS (SELECT 1
FROM dbo.taradod
WHERE IDP = a.IDP
AND Code = a.Code
...and other conditions which decide duplicate rows for you.)
Alternatively, you can delete rows from @taradodType
which already exist in dbo.taradod
and then execute your insert statement.
回答2:
It seems that you already have some data in dbo.taradod
, and while inserting new data from @taradodType
you want to filter out rows which are already exists in dbo.taradod
.
You can try select query like this:
SELECT * FROM @taradodType t1
left outer join dbo.taradod t2 on t1.IDP = t2.IDP
and t1.date = t2.date
where t2.IDP is null
回答3:
The easiest fix... Simply use the IGNORE_DUP_KEY = ON option when defining the index.
CREATE UNIQUE NONCLUSTERED INDEX ixu_IndexName ON dbo.taradodType (IDP)
WITH (DROP_EXISTING = ON, IGNORE_DUP_KEY = ON) ON [PRIMARY];
Rather than throwing an error when a dupe is encountered, it simply omits the offending row of data and moves forward like nothing happened.
HTH, Jason
来源:https://stackoverflow.com/questions/45906126/cannot-insert-into-table-with-types-in-sql-server