Jquery filter with multiple criteria

问题

I am trying to filter a list of restaurant's based on their influences. I would like to use sliders instead of generic categories like Indian/Asian/Mexican/European cuisine.

A restaurant could be

[{restaurant: 
    {name: 'The Apollon',
    thumb: 'apollon.jpg',
    type: 
        [{spicy: 5, type_id: 1}
        {garlic:3, type_id:2}
        {expensive:10, type_id:3}]}
}]

I'd then use a generic JQuery UI slider and pass the value from each slider to a hidden element.

Here is where I am utterly stuck though. I can get it to work on one slider by utilizing classes instead of JSON( .nospice .somespice .spicy ) and doing an if (value >= 7) {$('.spicy').show();}, but I'm not sure how I'd go about doing more advanced queries (if x = >=7 AND y = >=3 AND z = >=5)

Does someone want to nudge me in the right direction here? What do I need to read up on. If I am going about this in a fantasticly wrong way, please do tell.

jsfiddle: http://jsfiddle.net/techii/9e2cJ/

回答1:

jQuery has a .filter method. I would also recommend that you store the restaurant object with the div using .data to store the restaurant name and type with its div:

$(".restaurants > div").filter(function(){
   var info = $(this).data("info");
   // Some code to extract things like spicyness, expensiveness
   // Also some code to get the slider values...
   if (spicynessSliderValue <= spicyness && expensivenessSliderValue <= expensiveness)
   {
       return true;
   }
}).show();

In your case I would suggest using $.each however:

$(".restaurants > div").each(function(){
   ...
   var isMatch = picynessSliderValue <= spicyness && expensivenessSliderValue <= expensiveness;
   $(this).toggle(isMatch); // like .show or .hide, but takes a boolean
})

来源：https://stackoverflow.com/questions/14671821/jquery-filter-with-multiple-criteria