Populate a dictionary with the result of a query

问题

I'm currently doing this:

    cursor.execute('SELECT thing_id, thing_name FROM things')
    things = [];
    for row in cursor.fetchall():
        things.append(dict([('thing_id',row[0]),
                             ('thing_name',row[1])
                             ]))

Is there some shorthand I can use to do this, or should I write a little helper function?

回答1:

Using list comprehension:

things = [{'thing_id': row[0], 'thing_name': row[1]} for row in cursor.fetchall()]

or using list comprehension with zip:

things = [dict(zip(['thing_id', 'thing_name'], row)) for row in cursor.fetchall()]

If you use Cursor.description attribute, you can get column names:

names = [d.name for d in c.description]
things = [dict(zip(names, row)) for row in cursor.fetchall()]

回答2:

You could use MySQLdb.cursors.DictCursor class instead of MySQLdb.cursors.Cursor by passing cursor class to cursor method:

In [9]: cur = conn.cursor(MySQLdb.cursors.DictCursor)

In [10]: cur.execute('SELECT * FROM test_table')
Out[10]: 3L

In [11]: cur.fetchall()
Out[11]: 
({'create_time': datetime.datetime(2015, 12, 2, 10, 22, 23),
  'id': 1L,
  'name': 'Bob'},
 {'create_time': datetime.datetime(2015, 12, 2, 10, 22, 34),
  'id': 2L,
  'name': 'Stive'},
 {'create_time': datetime.datetime(2015, 12, 2, 10, 22, 37),
  'id': 3L,
  'name': 'Alex'})

来源：https://stackoverflow.com/questions/34034943/populate-a-dictionary-with-the-result-of-a-query