XMPP ( with smack) - Adding Friend

问题

In my chat application when I have to add a friend I have to follow this process -

Suppose A->B ist : A will send subscribe packet to B ( server entry shows NONE subscription ) iind - B will send subscribed packet to A ( server entry will be - TO/FROM) iiird - B will again send subscribe packet to A ( server entry TO/FROM ) ivth - A will send subscribed packet to B ( server entry BOTH )

Each time a notification is sent to the concerned user and after allowing corresponding packet is sent.

I want to do it like this -

When A sends a friend request to B ( a notification To B will be sent - and the server entry should be TO/FROM ) and its upto B to accept or not, If he accepts it then immediately the server entry should be BOTH.

Please tell me how can I achieve the same by sending only two sets of subscription packets.

Thanks

回答1:

AFAIK this can only be done on the client/library level: You have to implement the client so that for every confirmed subscription request, another subscription request is send back to the initial requester.

But you will always have 4 steps/packets to be send to "friend" to JIDs.