correct way to run setuid programs in C

问题

I have a process with permissions 4750. Two users exist in my Linux system. The root user and the appz user. The process inherits the permissions of a process manager that runs as "appz" user.

I have two basic routines:

void do_root (void)
{
        int status;
        status = seteuid (euid);
        if (status < 0) { 
        exit (status);
        }    
}

/* undo root permissions */
void undo_root (void)
{
int status;
        status = seteuid (ruid);
        if (status < 0) { 
                exit (status);
        }
        status = setuid(ruid);
        if (status < 0) { 
                exit (status);
        }
}

My flow is the following:

int main() {
 undo_root();
 do some stuff;
 do_root();
 bind( port 80); //needs root perm
 undo_root();
 while(1) {

    accept commads()
    if ( commands needs root user access)
    {
       do_root();
       execute();
       undo_root();

    }

 }

As you can see I want to execute some commands as root. I am trying to drop permissions temporarily and if the tasks needs root access I wrap the command between a do_root and undo_root call.

However it seems that my program is not working.

What is the canonical way to do it?

回答1:

The old-school way is to in both do_root and undo_root to use setreuid() to swap ruid and euid:

setreuid(geteuid(), getuid());

This is perfectly acceptable if the program is small enough to do a complete security audit.

The new-school way is far more complex and involves fork()ing off a child that accepts directives for what to do as root and then doing setuid(getuid()) to drop root permanently in the parent.. The child is responsible for validating all directives it receives. For a large enough program, this drops the amount of code that must be security audited, and allows the user to manage the process with job control or kill it, etc.

回答2:

There is a paper 'Setuid Demystified' by Hao Chen, David Wagner, and Drew Dean. It was presented at USENIX 2002. It describes how setuid() and transitions work in great detail (correct as of 2002). It is well worth reading (several times - I must be a year or two overdue on a re-read of it).

Fundamentally, as Petesh noted in a comment, when a process with EUID 0 does setuid(nuid) with nuid != 0, there is no way back to root (EUID 0) privileges. And, indeed, it is vital that it is so. Otherwise, when you login, the root process that logs you in could not limit you to your own privileges - you'd be able to get back to root. Saved UID complicates things, but I don't believe it affects the one-way trap of EUID 0 doing setuid().

回答3:

The setuid man page says the following:

... a set-user-ID-root program wishing to temporarily drop root privileges, assume the identity of a non-root user, and then regain root privileges afterwards cannot use setuid()

Meaning that you cannot use setuid(). You have to use seteuid() and, possibly, setreuid(). See Setuid Program Example for more details.

来源：https://stackoverflow.com/questions/9297415/correct-way-to-run-setuid-programs-in-c

标签

Linux

security

setuid