问题
I implement equals() the Java 7 way:
@Override
public boolean equals(Object obj)
{
if (this == obj) return true;
if (obj == null) return false;
if (getClass() != obj.getClass()) return false;
MyClass other = (MyClass) obj;
return Objects.equal(myFirstField, other.myFirstField) &&
Objects.equal(mySecondField, other.mySecondField);
}
Is there a way to reduce the code duplication?
I would prefer something like
@Override
public boolean equals(Object obj)
{
if (Objects.equalsEarlyExit(this, obj)) return Objects.equalstEarlyExitResult(this, obj);
MyClass other = (MyClass) obj;
return Objects.equal(myFirstField, other.myFirstField) &&
Objects.equal(mySecondField, other.mySecondField);
}
Or similar.
回答1:
Standard API Java with autoboxing and object creation inefficiencies:
import static java.util.Arrays.*;
import java.util.List;
class BrevityBeforeEfficiency {
int foo;
Object bar;
boolean baz;
@Override
public boolean equals(Object obj) {
return (obj instanceof BrevityBeforeEfficiency)
&& ((BrevityBeforeEfficiency) obj).values().equals(values());
}
@Override
public int hashCode() {
return values().hashCode();
}
private List<?> values() {
return asList(foo, bar, baz);
}
}
回答2:
You can use org.apache.commons.lang.builder.EqualsBuilder
from commons-lang
Example:
public boolean equals(Object other) {
return org.apache.commons.lang.builder.EqualsBuilder.reflectionEquals(this, other);
}
Other example:
private boolean equalsHelper(Object obj) {
if (obj == null) return false;
if (getClass() != obj.getClass()) return false;
return true;
}
public boolean equals(Object obj) {
if (this == obj) return true;
if(!equalsHelper(ob)) {
return false;
}
MyClass other = (MyClass) obj;
return new EqualsBuilder()
.append(myFirstField, other.myFirstField)
.append(mySecondField, other.mySecondField).isEquals()
}
回答3:
mixing in a bit of inheritance:
public abstract class BusinessObject
{
protected abstract Object[] getBusinessKeys();
@Override
public int hashCode()
{
return Objects.hash(getBusinessKeys());
}
@Override
public boolean equals(Object obj)
{
if(obj == null) return false;
if(obj == this) return true;
if(obj.getClass() != getClass()) return false;
BusinessObject other = (BusinessObject) obj;
return Arrays.deepEquals(this.getBusinessKeys(), other.getBusinessKeys());
}
}
so the only boilerplate code is to extend BusinessObject
and the single-lined getBusinessKeys()
:
public class Node extends BusinessObject
{
private final String code;
private final String name;
public Node(String code, String name)
{
this.code = code;
this.name = name;
}
@Override
protected Object[] getBusinessKeys()
{
return new Object[] { code, name };
}
}
It's the simplest and cleanest that I can think :)
回答4:
Here could be an implementation:
public abstract class EqualsHelper<T> {
@SuppressWarnings("unchecked")
public static <U> boolean equals(U that, Object other, EqualsHelper<U> equalsHelper) {
return that == other || other != null && that.getClass().equals(other.getClass()) && equalsHelper.equals(that, (U) other);
}
public abstract boolean equals(T that, T other);
}
Then:
@Override
public boolean equals(Object obj) {
return EqualsHelper.equals(this, obj, new EqualsHelper<MyClass>() {
@Override
public boolean equals(MyClass that, MyClass other) {
return Objects.equal(that.myFirstField, other.myFirstField)
&& Objects.equal(that.mySecondField, other.mySecondField);
}
});
}
I wonder if this can be considered as an anti-pattern, so don't hesitate to blame me if you think it actually is ;)
来源:https://stackoverflow.com/questions/25183872/can-java-help-me-avoid-boilerplate-code-in-equals