问题
I have been trying to figure out how to programmatically find a square root of a number in Swift. I am looking for the simplest possible way to accomplish with as little code needed. I now this is probably fairly easy to accomplish, but can't figure out a way to do it.
Any input or suggestions would be greatly appreciated.
Thanks in advance
回答1:
In Swift 3, the FloatingPoint
protocol appears to have a squareRoot()
method. Both Float
and Double
conform to the FloatingPoint
protocol. So:
let x = 4.0
let y = x.squareRoot()
is about as simple as it gets.
The underlying generated code should be a single x86 machine instruction, no jumping to the address of a function and then returning because this translates to an LLVM built-in in the intermediate code. So, this should be faster than invoking the C library's sqrt
function, which really is a function and not just a macro for assembly code.
In Swift 3, you do not need to import anything to make this work.
回答2:
Note that sqrt() will require the import of at least one of:
- UIKit
- Cocoa
- You can just import Darwin instead of the full Cocoa
- Foundation
回答3:
First import import UIKit
let result = sqrt(25) // equals to 5
Then your result should be on the "result" variable
回答4:
sqrt function for example sqrt(4.0)
回答5:
this should work for any root, 2 - ∞, but you probably don't care:
func root(input: Double, base: Int = 2) -> Double {
var output = 0.0
var add = 0.0
while add < 16.0 {
while pow(output, base) <= input {
output += pow(10.0, (-1.0 * add))
}
output -= pow(10.0, (-1.0 * add))
add += 1.0
}
return output + 0.0
}
来源:https://stackoverflow.com/questions/31146467/easiest-way-to-find-square-root-in-swift