How can I make a discrete state Markov model with pymc?

问题

I am trying to figure out how to properly make a discrete state Markov chain model with pymc.

As an example (view in nbviewer), lets make a chain of length T=10 where the Markov state is binary, the initial state distribution is [0.2, 0.8] and that the probability of switching states in state 1 is 0.01 while in state 2 it is 0.5

import numpy as np
import pymc as pm
T = 10
prior0 = [0.2, 0.8]
transMat = [[0.99, 0.01], [0.5, 0.5]]

To make the model, I make an array of state variables and an array of transition probabilities that depend on the state variables (using the pymc.Index function)

states = np.empty(T, dtype=object)
states[0] = pm.Categorical('state_0', prior0)
transPs = np.empty(T, dtype=object)
transPs[0] = pm.Index('trans_0', transMat, states[0])

for i in range(1, T):
    states[i] = pm.Categorical('state_%i' % i, transPs[i-1])
    transPs[i] = pm.Index('trans_%i' %i, transMat, states[i])

Sampling the model shows that the states marginals are what they should be (compared with model built with Kevin Murphy's BNT package in Matlab)

model = pm.MCMC([states, transPs])
model.sample(10000, 5000)
[np.mean(model.trace('state_%i' %i)[:]) for i in range(T)]

prints out:

[-----------------100%-----------------] 10000 of 10000 complete in 7.5 sec

[0.80020000000000002,
 0.39839999999999998,
 0.20319999999999999,
 0.1118,
 0.064199999999999993,
 0.044600000000000001,
 0.033000000000000002,
 0.026200000000000001,
 0.024199999999999999,
 0.023800000000000002]

My question is - this does not seem like the most elegant way to build a Markov chain with pymc. Is there a cleaner way that does not require the array of deterministic functions?

My goal is to write a pymc based package for more general dynamic Bayesian networks.

回答1:

As far as I know you have to encode the distribution of each time step as a deterministic function of the previous time step, because that's what it is--there's no randomness involved in the parameters because you defined them in the problem set-up. However, I think you're question may have been more towards finding a more intuitive way to represent the model. One alternative way would be to directly encode the time step transitions as a function of the previous time step.

from pymc import Bernoulli, MCMC

def generate_timesteps(N,p_init,p_trans):
    timesteps=np.empty(N,dtype=object)
    # A success denotes being in state 2, a failure being in state 1
    timesteps[0]=Bernoulli('T0',p_init)
    for i in xrange(1,N):
        # probability of being in state 1 at time step `i` given time step `i-1`
        p_i = p_trans[1]*timesteps[i-1]+p_trans[0]*(1-timesteps[i-1])
        timesteps[i] = Bernoulli('T%d'%i,p_i)
    return timesteps

timesteps = generate_timesteps(10,0.8,[0.001,0.5])
model = MCMC(timesteps)
model.sample(10000) # no burn in necessary since we're sampling directly from the distribution
[np.mean( model.trace(t).gettrace() ) for t in timesteps]

回答2:

In case you want to look at the long run behaviour of your Markov chain, the discreteMarkovChain package may be useful. The examples show some ideas for building up a discrete state Markov chain by defining a transition function that tells you for each state the reachable states in the next step and their probabilities. You could use that same function to simulate the process.

来源：https://stackoverflow.com/questions/22636974/how-can-i-make-a-discrete-state-markov-model-with-pymc

标签

python

markov-chains

pymc