问题
I am extending an existing library by creating a child class which extends to the library class.
In the child class, I was able to test most of functionality in initialize
method, but was not able to mock super
call. The child class looks like something like below.
class Child < SomeLibrary
def initialize(arg)
validate_arg(arg)
do_something
super(arg)
end
def validate_arg(arg)
# do the validation
end
def do_something
@setup = true
end
end
How can I write rspec test (with mocha) such that I can mock super
call? Note that I am testing functionality of initialize
method in the Child
class. Do I have to create separate code path which does not call super
when it is provided with extra argument?
回答1:
You can't mock super
, and you shouldn't. When you mock something, you are verifying that a particular message is received, and super
is not a message -- it's a keyword.
Instead, figure out what behavior of this class will change if the super
call is missing, and write an example that exercises and verifies that behavior.
回答2:
A good way to test this is to set an expectation of some action taken by the superclass - example :
class Some::Thing < Some
def instance_method
super
end
end
and the super class:
class Some
def instance_method
another_method
end
def self.another_method # not private!
'does a thing'
end
end
now test :
describe '#instance_method' do
it 'appropriately triggers the super class method' do
sawm = Some::Thing.new
expect(sawm).to receive(:another_method)
sawm.instance_method
end
end
All This Determines Is That Super Was Called On the Superclass
This pattern's usefulness is dependent on how you structure your tests/what expectations you have of the child/derivative class' mutation by way of the super
method being applied.
Also - pay close attention to class
and instance
methods, you will need to adjust allows
and expects
accordingly
YMMV
回答3:
A bit late to this party, but what you can also do is forego using the super
keyword and instead do
class Parent
def m(*args)
end
end
class Child < Parent
alias super_m m
def m(*args)
super_m(*args)
end
end
That way your super method is accessible like any other method and can e.g. be stubbed like any other method. The main downside is that you have to explicitly pass arguments to the call to the super method.
来源:https://stackoverflow.com/questions/15856334/how-can-i-mock-super-in-ruby-using-rspec