Find value from one csv in another one (like vlookup) in bash (Linux)

问题

I have already tried all options that I found online to solve my issue but without good result.

Basically I have two csv files (pipe separated):

file1.csv:

123|21|0452|IE|IE|1|MAYOBAN|BRIN|OFFICE|STREET|MAIN STREET|MAYOBAN|

123|21|0453|IE|IE|1|CORKKIN|ROBERT|SURNAME|CORK|APTS|CORKKIN|

123|21|0452|IE|IE|1|CORKCOR|NAME|HARRINGTON|DUBLIN|STREET|CORKCOR|

file2.csv:

MAYOBAN|BANGOR|2400

MAYOBEL|BELLAVARY|2400

CORKKIN|KINSALE|2200

CORKCOR|CORK|2200

DUBLD11|DUBLIN 11|2100

I need a linux bash script to find the value of pos.3 from file2 based on the content of pos7 in file1.

Example: file1, line1, pos 7: MAYOBAN find MAYOBAN in file2, return pos 3 (2400)

the output should be something like this:

2400

2200

etc...

Please help Jacek

回答1:

A little approach, far away to be perfect:

DELIMITER="|"

for i in $(cut -f 7 -d "${DELIMITER}" file1.csv ); 
do 
    grep "${i}" file2.csv | cut -f 3 -d "${DELIMITER}"; 
done

回答2:

This will work, but since the input files must be sorted, the output order will be affected:

join -t '|' -1 7 -2 1 -o 2.3 <(sort -t '|' -k7,7 file1.csv) <(sort -t '|' -k1,1 file2.csv)

The output would look like:

2200
2200
2400

which is useless. In order to have a useful output, include the key value:

join -t '|' -1 7 -2 1 -o 0,2.3 <(sort -t '|' -k7,7 file1.csv) <(sort -t '|' -k1,1 file2.csv)

The output then looks like this:

CORKCOR|2200
CORKKIN|2200
MAYOBAN|2400

Edit:

Here's an AWK version:

awk -F '|' 'FNR == NR {keys[$7]; next} {if ($1 in keys) print $3}' file1.csv file2.csv

This loops through file1.csv and creates array entries for each value of field 7. Simply referring to an array element creates it (with a null value). FNR is the record number in the current file and NR is the record number across all files. When they're equal, the first file is being processed. The next instruction reads the next record, creating a loop. When FNR == NR is no longer true, the subsequent file(s) are processed.

So file2.csv is now processed and if it has a field 1 that exists in the array, then its field 3 is printed.

回答3:

cut -d\| -f7 file1.csv|while read line
do 
  grep $line file1.csv|cut -d\| -f3
done

来源：https://stackoverflow.com/questions/10697724/find-value-from-one-csv-in-another-one-like-vlookup-in-bash-linux

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