问题
In C/C++ how can I calculate (a^b)%m where b does not fit into 64 bits? In other words, is there a way of calculating the above value using b%m instead of b?
And is there any algorithm that can compute the above result in O(log(b)) time or O(log(b%m)) time?
回答1:
According to Euler's theorem, if a and m are coprime:
ab mod m = ab mod phi(m) mod m
so if b is large, you can use the value b % phi(m) instead of b. phi(m) is Euler's totient function, which can be easily calculated if you know the prime factorization of m.
Once you've reduced the value of b in this way, use Exponentiation by squaring to compute the modular exponentiation in O(log (b % phi(m))).
来源：https://stackoverflow.com/questions/11448658/modular-exponentiation