问题
I'm using a ContextMenuStrip
for multiple controls and I'm trying to figure out the best way to get the control that was actually clicked on to open the Context Menu. The sender just gives the ToolStripMenuItem
reference, which has an Owner property that references the ContextMenuStrip
, but I cannot figure out how to tell which control the click came from. There must be a simple way to check this, right? I'm checking it in the ToolStripMenuItem
's click event.
Friend WithEvents mnuWebCopy As System.Windows.Forms.ToolStripMenuItem
...
Private Sub mnuWebCopy_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles mnuWebCopy.Click
I found a similar post about this, but that mentions using a SourceControl
property which I do not see on here.
I'm using Visual Studio 2008, VB.Net winforms.
回答1:
Private Sub mnuWebCopy_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles mnuWebCopy.Click
Dim myItem As ToolStripMenuItem = CType(sender, ToolStripMenuItem)
Dim cms As ContextMenuStrip = CType(myItem.Owner, ContextMenuStrip)
MessageBox.Show(cms.SourceControl.Name)
End Sub
回答2:
Your sender is a ToolStripMenuItem -- cast it.
Its owner is a ContextMenuStrip -- get it.
SourceControl is a property on the ContextMenuStrip and references the last control from which the ContextMenuStrip was displayed.
回答3:
Private Sub kdgToolStripMenuItem_Click(sender As Object, e As EventArgs) Handles kdgToolStripMenuItem.Click
Dim sms = (sender.GetCurrentParent()).SourceControl.name
MsgBox(sms)
End Sub
'///Faster
回答4:
Private Sub cmsRightClick_Click(ByVal sender As Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles cmsRightClick.MouseClick
Dim s As String = CType(sender, ContextMenuStrip).GetItemAt(CType(sender, ContextMenuStrip).DisplayRectangle.X, _
CType(sender, ContextMenuStrip).DisplayRectangle.Y + e.Y).Text.Trim()
MsgBox(s)
Select Case s
Case Is = "Select Summary Total"
Dim x = 0
Case Is = "Select Collections"
Dim x = 1
Case Is = "UnSelect"
Dim x = 2
Case Is = "Reconcile"
Dim x = 3
Case Is = "Undo Reconciliation"
Dim x = 4
End Select
End Sub
回答5:
On VB.NET 2013 this work so fine:
Dim cms As ContextMenuStrip = CType(sender, ContextMenuStrip)
MessageBox.Show(cms.SourceControl.Name)
来源:https://stackoverflow.com/questions/2074898/how-do-you-get-the-control-that-was-clicked-to-open-a-contextmenustrip