问题
So in Python 3, you can generate an ISO 8601 date with .isoformat(), but you can't convert a string created by isoformat() back into a datetime object because Python's own datetime directives don't match properly. That is, %z = 0500 instead of 05:00 (which is produced by .isoformat()).
For example:
>>> strDate = d.isoformat()
>>> strDate
'2015-02-04T20:55:08.914461+00:00'
>>> objDate = datetime.strptime(strDate,"%Y-%m-%dT%H:%M:%S.%f%z")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python34\Lib\_strptime.py", line 500, in _strptime_datetime
tt, fraction = _strptime(data_string, format)
File "C:\Python34\Lib\_strptime.py", line 337, in _strptime
(data_string, format))
ValueError: time data '2015-02-04T20:55:08.914461+00:00' does not match format '%Y-%m-%dT%H:%M:%S.%f%z'
From Python's strptime documentation: (https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior)
%z UTC offset in the form +HHMM or -HHMM (empty string if the the object is naive). (empty), +0000, -0400, +1030
So, in short, Python does not even adhere to its own string formatting directives.
I know datetime is already terrible in Python, but this really goes beyond unreasonable into the land of plain stupidity.
Tell me this isn't true.
回答1:
As it turns out, this is the current best "solution" to this question:
pip install python-dateutil
Then...
import datetime
import dateutil.parser
def getDateTimeFromISO8601String(s):
d = dateutil.parser.parse(s)
return d
回答2:
Try this:
>>> def gt(dt_str):
... dt, _, us= dt_str.partition(".")
... dt= datetime.datetime.strptime(dt, "%Y-%m-%dT%H:%M:%S")
... us= int(us.rstrip("Z"), 10)
... return dt + datetime.timedelta(microseconds=us)
Usage:
>>> gt("2008-08-12T12:20:30.656234Z")
datetime.datetime(2008, 8, 12, 12, 20, 30, 656234)
来源：https://stackoverflow.com/questions/28331512/how-to-convert-pythons-isoformat-string-back-into-datetime-object