问题
I, for some reason, can't change the zIndex of an element using jQuery. I've searched all of this website and Google but couldn't find the right answer. I am trying to put my element in front of another div when clicking a button. I used the code you can see under here. But didn't work.
$(this).parent().css('zIndex',3000);
CSS code of elements it's under in the begin:
#wall{
width:100%;
height:700px;
position: absolute;
top:500px;
background: #11c1e7;
opacity: 0.6;
z-index: 900;
}
CSS code of element that should go above this:
.port1 {
width:200px;
height:200px;
left:<?php echo rand(1,1000); ?>px;
top:-500px;
border-radius: 500px;
background:red;
position:absolute;
z-index: 10;
}
Does anyone know how I can fix this?
// Edit
Link to the site: http://dannypostma.com/project/j.php
When clicking the portfolio ball, two balls drop from the air. These should go in front of the water when clicked.
回答1:
Setting the style.zIndex
property has no effect on non-positioned elements, that is, the element must be either absolutely positioned, relatively positioned, or fixed.
So I would try:
$(this).parent().css('position', 'relative');
$(this).parent().css('z-index', 3000);
回答2:
That's invalid Javascript syntax; a property name cannot have a -
.
Use either zIndex
or "z-index"
.
回答3:
$(this).parent().css('z-index',3000);
回答4:
because your jQuery code is wrong. Correctly would be:
var theParent = $(this).parent().get(0);
$(theParent).css('z-index', 3000);
回答5:
zIndex
is part of javaScript notation.(camelCase)
but jQuery.css uses same as CSS syntax.
so it is z-index
.
you forgot .css("attr","value"). use ' or " in both, attr and val. so,
.css("z-index","3000");
来源:https://stackoverflow.com/questions/8201855/cant-change-z-index-with-jquery