Int tokenizer | 易学教程

问题

I know there are string tokenizers but is there an "int tokenizer"?

For example, I want to split the string "12 34 46" and have:

list[0]=12

list[1]=34

list[2]=46

In particular, I'm wondering if Boost::Tokenizer does this. Although I couldn't find any examples that didn't use strings.

回答1:

Yes there is: use a stream, e.g. a stringstream:

stringstream sstr("12 34 46");
int i;
while (sstr >> i)
    list.push_back(i);

Alternatively, you can also use STL algorithms and/or iterator adapters combined with constructors:

vector<int> list = vector<int>(istream_iterator<int>(sstr), istream_iterator<int>());

回答2:

The C++ String Toolkit Library (StrTk) has the following solution to your problem:

#include <string>
#include <deque>
#include "strtk.hpp"

int main()
{ 
   {
      std::string data = "12 34 46";
      std::deque<int> int_list;
      strtk::parse(data," ",int_list);
   }

   {
      std::string data = "12.12,34.34|46.46 58.58";
      std::deque<double> double_list;
      strtk::parse(data," ,|",double_list);
   }

   return 0;
}

More examples can be found Here

Note: The parsing process is EXTREMELY fast and efficient, putting stdlib and boost based solutions to shame.

回答3:

What you're looking for is 2 separate actions. First tokenize the string, then convert each token to an int.

回答4:

i am not sure if you can do this without using string or char* because you have to but both numbers and spaces into same set...

来源：https://stackoverflow.com/questions/1141741/int-tokenizer

标签

c++

tokenize