echo innerHTML, without outer node tags

问题

I'm using the DOMDocument class to parse a fairly unpredictable string of markup. It's not all that well formed and I need some data from it. Regex's are right out, of course.
So far, I've got this:

$dom = new DOMDocument;
$dom->loadHTML($str);
$contents = $dom->getElementsByTagName('body')->item(0);
echo $dom->saveXML($contents);

Now this gives me:

<body>
    <p>What I'm really after</p>
    <ul><li>Foo</li><li>Bar</li></ul>
    <h6>And so on</h6>
</body>

What really annoys me are those <body> tags. I want them gone. After grazing the web, I've stumbled across the weirdest workarounds. Some more hacky than others, so in the end, I settled for:

echo substr($dom->saveXML($contents), 6, -7);

Still feels hacky to me, but it's the best I could find. Is there a more reliable way of getting the innerHTML of the DOM, starting from a given node, without the corresponding tags actually showing up?

I've seen suggestions using regex's (a no-no IMHO), or even looping through all the children, echoing those that have childNodes of their own, and stringing together those that don't:

if ($contents->hasChildNodes())
{
    $children = $contents->getElementsByTagName('*');
    foreach($children as $child)
    {
        if ($child->hasChildNodes() || $child->nodeName === 'br')
        {//or isset($standaloneNodes[$child->nodeName])
            echo $dom->saveXML($child);
            continue;
        }

        echo '<'.$child->nodeName.'>'.$child->nodeValue.'</'.$child->nodeName.'>';
    }
}

But that, to me, seems even more absurd...

回答1:

When exporting HTML, you must have a single root element. In most cases, the most useful one is the body. Since you're loading in an HTML fragment, you know for certain that it won't have any attributes, therefore the substr(...,6,-7) is perfectly predictable and fine.

来源：https://stackoverflow.com/questions/16840683/echo-innerhtml-without-outer-node-tags

标签

php

dom

domdocument