问题
Okay, I did a mistake and blindly copied and pasted a ''code snippet' that is supposed to restrict the user from typing down ANYTHING ELSE other than a number in a Bootstrap input field.
By blindly doing that, i did not really understood how it's supposed to work. Now i need to allow the decimal point, the "." to be typed down and i don't know what i need to change.
Can someone explain the snippet below or provide a resource?
$('#elementXPosition,#elementYPosition,#elementWidth,#elementHeight').keypress(function(e) {
var a = [];
var k = e.which;
for (i = 48; i < 58; i++)
a.push(i);
if (!(a.indexOf(k)>=0))
e.preventDefault();
});
回答1:
Here is the solution I am able to create for you
There are two possible solutions to go with and I would prefer to go with HTML's pattern
feature.
**HTML**
<input type="text" id="elementXPosition" pattern="[0-9.]+" title="Please enter decimal numbers only" placeholder="Using pattern" />
<input type="text" id="elementYPosition" placeholder="Using jQuery" />
**jQuery**
$(document).ready(function () {
$("#elementYPosition").keydown(function (e) {
/*To check if shift key was pressed*/
if (e.shiftKey == true) {
e.preventDefault();
}
/*Allows some keys to be pressed*/
if ((e.keyCode >= 48 && e.keyCode <= 57) || (e.keyCode >= 96 && e.keyCode <= 105) || e.keyCode == 8 || e.keyCode == 9 || e.keyCode == 37 || e.keyCode == 39 || e.keyCode == 46 || e.keyCode == 190) {} else {
e.preventDefault();
}
/*This will allow the '.' to be pressed only once*/
if ($(this).val().indexOf('.') !== -1 && e.keyCode == 190) e.preventDefault();
});
});
Also here is the list of key codes you might need to edit the code as per your wish.
Hopefully it helps.
来源:https://stackoverflow.com/questions/21966669/jquery-restricting-certain-numbers-from-being-typed-in-a-bootstrap-input