问题
I am trying to read a single character multiple times. The catch is that I need to prevent user errors. So for example:
char arr[10];
for(int i = 0; i < 10; i++)
{
cin.get(arr[i]);
}
Where the inputs should be something like a, b, c, d, ...
. But if someone were to enter ab
for the first entry I want to capture the a
and then ignore the b
. I know about cin.ignore
however I don't know how I would go about ignoring an arbitrary number of alphanumeric characters or symbols considering that I want to ignore a potentially unlimited number of characters and then stop ignoring and read again.
How can I either ignore an arbitrary number of characters and then stop ignoring or how can I actually flush the buffer for cin.
回答1:
Most input is line feed so if you want to ignore all characters in the input stream until you hit a newline then you could use:
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n')
Since we ignore up to the streamsize
there should not be an extra content in the input buffer.
回答2:
If you want user to hit enter after each symbol, then code could be as simple as this:
char arr[10];
for(int i = 0; i < 10; )
{
std::string line;
std::getline( std::cin, line );
// check that line is not empty
if( line.empty() ) {
std::cout << "missing input" << std::endl;
continue;
}
arr[i++] = line[0]; // get only first symbol and ignore the rest
}
if you have something else in mind, I am afraid that will not work with std::cin
- you do not see any input until user presses enter. In that case you would have to use OS specific functions to get unbuffered input.
回答3:
The following is the code that you want, if your inputing like this a 'enter' b 'enter' c 'enter' etc...
#include <iostream>
#include <string>
using namespace std;
int main() {
char arr[10];
string line;
for (int i = 0; i < 10; i++)
{
getline(cin, line);
arr[i] = line[0];
cout << endl << "Here is the Char: " << arr[i] << endl;
}
return 0;
}
BUT if you enter input like this in one line: a,b,c,d,e,f,g,h,i,j 'enter'
then you want the following code:
#include <iostream>
#include <string>
using namespace std;
int main() {
char arr[10];
string line;
int i = 0;
size_t end;
getline(cin, line);
end = 0;
int counter = 0;
if (line != "") {
while (end != string::npos && counter < 10) {
if (counter == 0) {
arr[counter] = line[0];
}
else {
end = line.find(",", end + 1);
arr[counter] = line[end + 1];
}
counter++;
}
}
for (int i = 0; i < 10; i++) {
cout << endl << "Here is the Char: " << arr[i] << endl;
}
return 0;
}
来源:https://stackoverflow.com/questions/32895730/how-do-you-flush-the-contents-of-stdcin-before-an-additional-read-from-it