问题
I would like to sample from a multinomial distribution. I would do this by using sample and specifying some probabilites. E.g: I have 3 categories, and I want to sample 10 times.
> my_prob = c(0.2, 0.3, 0.5)
> x = sample(c(0:2), 100, replace = T, prob = my_prob)
> head(x)
[1] 2 0 2 1 1 2
My setting is now only different in the following aspect: I want to sample a lot (e.g. 1e09) numbers. And actually I am only interested in the frequency of each category. So in the above mentioned example this would mean:
> table(x)
x
0 1 2
27 29 44
Does anybody have an idea how to compute this as efficient as possible?
thanks, steffi
回答1:
You need rmultinom.
my_prob <- c(0.2,0.3,0.5)
number_of_experiments <- 10
number_of_samples <- 100
experiments <- rmultinom(n=number_of_experiments, size=number_of_samples, prob=my_prob)
experiments
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 14 18 15 19 14 17 23 18 24 15
[2,] 33 34 36 30 40 30 27 38 24 30
[3,] 53 48 49 51 46 53 50 44 52 55
回答2:
If the problem is that you can't fit a vector of length 1e9 into RAM, then you can repeatedly calculate the table for a smaller number of samples and add up the totals.
n_total <- 1e9
n_chunk <- 1e6
n_iter <- n_total / n_chunk
my_prob = c(0.2, 0.3, 0.5)
totals <- numeric(3)
for(i in seq_len(n_iter))
{
totals <- totals + table(sample(0:2, n_chunk, replace = TRUE, prob = my_prob))
}
totals
stopifnot(sum(totals) == n_total)
Like Max said, you might prefer rmultinom
over sample. Take the rowSums
of his experiments
variable.
来源:https://stackoverflow.com/questions/7915668/draw-a-huge-sample-1e09-from-a-multinomial-distribution-with-sample