问题
I am using optparse
to get command line input.
Lets say that I am running a script demo.py
and it creates some output. But unless I specify the command line input, the output is not written to a file.
I am trying to do the following:
python demo.py
in command line should run the script, but not write the output anywhere.
python demo.py -o
in command line should write the output to my default file name output.txt
.
python demo.py -o demooutput.txt
in command line should write the output to file demooutput.txt
.
PS: I would not prefer to switch to argparse
from optparse
.
回答1:
You can use optparse-callbacks to achieve this.
Here is how it wiill work for your use case.
parser.add_option("-o", action="callback", dest="output", callback=my_callback)
def my_callback(option, opt, value, parser):
if len(parser.rargs) > 0:
next_arg = parser.rargs[0]
if not next_arg.startswith("-"):
# Next argument is not another option
del parser.rargs[0]
setattr(parser.values, option.dest, next_arg)
return
# If not processed, set the default value
setattr(parser.values, option.dest, "output.txt")
回答2:
I don't think there is unfortunately - the only way I can think of is hacking around the problem by adding your own logic statements. The following code should do the trick.
import re, sys
import optparse from OptionParser
usage = "usage: %prog [options] arg"
parser = OptionParser(usage)
if '-f' in argv:
a = argv.index('-f')
if (a != len(argv)-1) and re.search('[.]txt', argv[a+1]):
parser.add_option("-f", "--foo", dest="foo")
else:
parser.add_option("-f", dest="foo", action="store_true")
回答3:
This doesn't answer the direct question, 'how to define an Action...', but it handles the inputs in a simple way.
Set '-o'
to be 'store_true'
. If True check the 'args'
variable for a file name.
(options, args) = parser.parse_args()
if options.o:
if args:
dest = args[0]
else:
dest = 'output.txt'
else:
dest = ''
(In argparse
the equivalent would be to define a positional argument with nargs='?'
.)
If these are the only arguments, you could also get by with checking for the filename without requiring the `-o'
.
Another possibility - 'store_const', with the positional 'filename' having priority:
parser = optparse.OptionParser()
parser.add_option('-o',dest='dest',action='store_const', const='output.txt', default='')
(options, args) = parser.parse_args()
if args:
options.dest = args[0]
print options
来源:https://stackoverflow.com/questions/21722509/python-can-optparse-have-the-action-attribute-to-act-both-like-store-and-store