How to convert Platform::String to char*?

大兔子大兔子 提交于 2019-11-27 09:25:18

Platform::String::Data() will return a wchar_t const* pointing to the contents of the string (similar to std::wstring::c_str()). Platform::String represents an immutable string, so there's no accessor to get a wchar_t*. You'll need to copy its contents, e.g. into a std::wstring, to make changes.

There's no direct way to get a char* or a char const* because Platform::String uses wide characters (all Metro style apps are Unicode apps). You can convert to multibyte using WideCharToMultiByte.

Here is a very simple way to do this in code w/o having to worry about buffer lengths. Only use this solution if you are certain you are dealing with ASCII:

Platform::String^ fooRT = "aoeu";
std::wstring fooW(fooRT->Begin());
std::string fooA(fooW.begin(), fooW.end());
const char* charStr = fooA.c_str();

Keep in mind that in this example, the char* is on the stack and will go away once it leaves scope

Jeff McClintock

You shouldn't cast a wide character to a char, you will mangle languages using more than one byte per character, e.g. Chinese. Here is the correct method.

#include <cvt/wstring>
#include <codecvt>

Platform::String^ fooRT = "foo";
stdext::cvt::wstring_convert<std::codecvt_utf8<wchar_t>> convert;
std::string stringUtf8 = convert.to_bytes(fooRT->Data());
const char* rawCstring = stringUtf8.c_str();

There's the String::Data method returning const char16*, which is the raw unicode string.

Conversion from unicode to ascii or whatever, i.e. char16* to char*, is a different matter. You probably don't need it since most methods have their wchar versions these days.

A solution using wcstombs:

Platform::String^ platform_string = p_e->Uri->AbsoluteUri;
const wchar_t* wide_chars =  platform_string->Data();
char chars[512];
wcstombs(chars, wide_chars, 512);
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!