问题
self.data = sorted(self.data, key=attrgetter('word'))
self.data is a list of Word objects. Word objects have 'word', 'definition', 'example' and 'difficulty' attributes. I want to sort by the 'word' strings of each Word object, and the code above does that except it's not case insensitive. How would I go about making the sorting case insensitive?
I've tried the solutions from another question asked here, but when I tried it, it said "TypeError: 'Word' object is not subscriptable". What could I do to make it work?
Thanks.
回答1:
You can write your own key function:
self.data = sorted(self.data, key = lambda w: w.word.lower())
回答2:
Try something like:
self.data = sorted(self.data, key=lambda w: attrgetter('word')(w).lower())
Though, with that you would probably be much better off simply using:
self.data = sorted(self.data, key=lambda w: w.word.lower()
来源：https://stackoverflow.com/questions/7656339/python-how-to-sort-a-list-of-objects-using-attrgetter-with-case-insensitivity