Is it possible to track visitor that leave or page to another sites?

问题

Is it possible to track visitor that leave or page to another sites, like ask question only when they want move to another sites or other domain name? I write this code

<script language="JavaScript">
  window.onbeforeunload = confirmExit;
  function confirmExit()
  {
    return "leave?";
  }
</script>

But this code work everytime even on my own pages. I want to make this code to run just if visitors go to another domain by tiping URL (Not by links). Is it possible? Thanks

回答1:

I think this is a task for a browser plugin, not a page script. It's not possible for JS to know what the user does outside the page.

If this were possible, that would be a whole new security problem, a privacy issue, and I won't visit your site.

回答2:

As you have tagged jquery in this question I guess you are already using http://jquery.com/

<script language="JavaScript">
  $(document).ready(function(){
       $("a").click(function(){
       if( fnGetDomain(document.location) == fnGetDomain($(this).attr("href")) )
       {
            return true;
       }
       else{
            return confirm("Leave page?");
       }

   });
});
function fnGetDomain(url) {
  return url.match(/:\/\/(.[^/]+)/)[1];
}
</script>

You can use document.location.href in place of document.location if there is any problem

回答3:

I've tried a thing here, not sure it works on every cases...

window.onbeforeunload = confirmExit;

function confirmExit(event)
{
    console.log(event);
    console.log("Current : " + event.srcElement.domain);
    console.log("Target : " + event.target.domain);
    if (event.srcElement.domain != event.target.domain)
    {
        return "leave ?";
    }
    else
    {
        // staying here
    }
}

来源：https://stackoverflow.com/questions/10563284/is-it-possible-to-track-visitor-that-leave-or-page-to-another-sites

标签

javascript

jquery

tracking