问题
I am working on a food website and have noticed an issue when I display the users cart, currently the table header is called per item which is taken from mySQL, which looks like this:
Here is my current code:
function cart() {
foreach($_SESSION as $name => $value) {
if ($value>0){
if (substr($name, 0, 5)=='cart_') {
$id = substr($name, 5, (strlen($name)-5));
$get = mysql_query('SELECT id, name, price FROM products WHERE id='.mysql_real_escape_string((int)$id));
while ($get_row = mysql_fetch_assoc($get)) {
$sub = $get_row['price']*$value;?>
<center>
<table class='menufinal' border=0 width=75%>
<th>Remove Item</th>
<th>Item Name</th>
<th>Item Price</th>
<th>Quantity</th>
<th>Line Total</th>
<tr>
<td><?echo '<a href="cart.php?delete=' .$id.'"><img src="x.png"></a><br>'?></td>
<td><?echo $get_row['name']?></td>
<td><?echo '£' . number_format($get_row['price'], 2);?></td>
<td><?echo '<a href="cart.php?remove=' .$id. '"style="text-decoration:none">- </a>' .$value. '<a href="cart.php?add=' .$id. '"style="text-decoration:none"> +</a>' ?> </td>
<td> <?echo '£ ' . number_format($sub, 2);?> </td>
</tr>
<?
}
}
if (empty($total)) {
if (empty($sub)) {
//do nothing
} else {
$total = $sub;
}
} else {
$total += $sub;
}
}
}
if (!empty($total)){
echo '<br>Total: £' . number_format($total, 2) . '<br>';
echo '<div id="dorc"><p><a href="index.php"><img src="dishes.png" width="240" height="152"></a> <img src="spacer.png" width="200"> <a href="checkout.php"><img src="checkout.png" width="240" height="152"></a>';
}
else {
header ('Location: index.php');
}
}
My question is how can I get it to display the table header only once and also why is there an additional item being printed to the bottom of the screen alone?
回答1:
Just move the table and header tags outside of the loop.
Do something like:
<table>
<th></th> #define all table headers
for each item:
<tr>
<td>item info</td>...
</tr>
</table>
回答2:
use this
<?php
function cart() {
foreach($_SESSION as $name => $value) {
if ($value>0){
if (substr($name, 0, 5)=='cart_') {
$id = substr($name, 5, (strlen($name)-5));
$get = mysql_query('SELECT id, name, price FROM products WHERE id='.mysql_real_escape_string((int)$id));?>
<center>
<table class='menufinal' border=0 width=75%>
<th>Remove Item</th>
<th>Item Name</th>
<th>Item Price</th>
<th>Quantity</th>
<th>Line Total</th>
<?php while ($get_row = mysql_fetch_assoc($get)) {
$sub = $get_row['price']*$value;?>
<tr>
<td><?echo '<a href="cart.php?delete=' .$id.'"><img src="x.png"></a><br>'?></td>
<td><?echo $get_row['name']?></td>
<td><?echo '£' . number_format($get_row['price'], 2);?></td>
<td><?echo '<a href="cart.php?remove=' .$id. '"style="text-decoration:none">- </a>' .$value. '<a href="cart.php?add=' .$id. '"style="text-decoration:none"> +</a>' ?> </td>
<td> <?echo '£ ' . number_format($sub, 2);?> </td>
</tr>
<?
}
}
if (empty($total)) {
if (empty($sub)) {
//do nothing
} else {
$total = $sub;
}
} else {
$total += $sub;
}
}
}
if (!empty($total)){
echo '<br>Total: £' . number_format($total, 2) . '<br>';
echo '<div id="dorc"><p><a href="index.php"><img src="dishes.png" width="240" height="152"></a> <img src="spacer.png" width="200"> <a href="checkout.php"><img src="checkout.png" width="240" height="152"></a>';
}
else {
header ('Location: index.php');
}
}
来源:https://stackoverflow.com/questions/27879328/php-mysql-displaying-only-one-header-for-items