Using linear regression (lm) in R caret, how do I force the intercept through 0? [duplicate]

问题

This question already has answers here:

Fit a no-intercept model in caret (2 answers)

Closed 3 months ago.

I'm trying to use R caret to perform cross-validation of my linear regression models. In some cases I want to force the intercept through 0. I have tried the following, using the standard lm syntax:

regressControl  <- trainControl(method="repeatedcv",
                        number = 4,
                        repeats = 5
                        )                      

regress         <- train(y ~ 0 + x,
               data = myData,
               method  = "lm",
               trControl = regressControl)

Call:
lm(formula = .outcome ~ ., data = dat)

Coefficients:
(Intercept)     x 
-0.0009585    0.0033794  `

This syntax seems to work with the standard 'lm' function but not within the caret package. Any suggestions?

test <- lm(y ~ 0 + x,
       data = myData)


Call:
lm(formula = y ~ 0 + x, data = myData)

Coefficients:
x 
0.003079 

回答1:

You can take advantage of the tuneGrid parameter in caret::train.

regressControl  <- trainControl(method="repeatedcv",
                    number = 4,
                    repeats = 5
                    ) 

regress <- train(mpg ~ hp,
           data = mtcars,
           method  = "lm",
           trControl = regressControl, 
           tuneGrid  = expand.grid(intercept = FALSE))

Use getModelInfo("lm", regex = TRUE)[[1]]$param to see all the things you could have tweaked in tuneGrid (in the lm case, the only tuning parameter is the intercept). It's silly that you can't simply rely on formula syntax, but alas.

来源：https://stackoverflow.com/questions/41730532/using-linear-regression-lm-in-r-caret-how-do-i-force-the-intercept-through-0