Groovy - XML to JSON without knowing each key

问题

I have an XML web service response (see below) and would like to convert it to JSON, without knowing each key.

The response is much bigger, this is just a sample showing the structure.

Is this possible to do in Groovy?

<allMortProdContainers>
   <WsMortProdContainerv02>
      <allWsMortProdCapCollarBandByEnd xsi:nil="true"/>
      <allWsMortProdCashBackBandByEnd xsi:nil="true"/>
      <allWsMortProdEarlyRepaymentBandByEnd>
         <WsMortProdEarlyRepaymentBandv01>
            <endDate>???</endDate>
            <endMonth>???</endMonth>
            <fixedCharge>???</fixedCharge>
            <monthsInterest>???</monthsInterest>
            <percentage>???</percentage>
         </WsMortProdEarlyRepaymentBandv01>
      </allWsMortProdEarlyRepaymentBandByEnd>
      <myWsMortProdSpec>
         <productBaseRate>???</productBaseRate>
         <productBaseRateDescription>???</productBaseRateDescription>
         <productCode>???</productCode>
         <productDescription>???</productDescription>
         <productDescriptionWebFriendly>???</productDescriptionWebFriendly>
         <productInfoKey>???</productInfoKey>
         <productType>???</productType>
      </myWsMortProdSpec>
   </WsMortProdContainerv02>
</allMortProdContainers>

回答1:

@Grab(group='org.json', module='json', version='20180130')
import org.json.XML;

def xml = '''<allMortProdContainers xmlns:xsi="...." >
   <WsMortProdContainerv02>
      <allWsMortProdCapCollarBandByEnd xsi:nil="true"/>
      <allWsMortProdCashBackBandByEnd xsi:nil="true"/>
      <allWsMortProdEarlyRepaymentBandByEnd>
         <WsMortProdEarlyRepaymentBandv01>
            <endDate>???</endDate>
            <endMonth>???</endMonth>
            <fixedCharge>???</fixedCharge>
            <monthsInterest>???</monthsInterest>
            <percentage>???</percentage>
         </WsMortProdEarlyRepaymentBandv01>
      </allWsMortProdEarlyRepaymentBandByEnd>
      <myWsMortProdSpec>
         <productBaseRate>???</productBaseRate>
         <productBaseRateDescription>???</productBaseRateDescription>
         <productCode>???</productCode>
         <productDescription>???</productDescription>
         <productDescriptionWebFriendly>???</productDescriptionWebFriendly>
         <productInfoKey>???</productInfoKey>
         <productType>???</productType>
      </myWsMortProdSpec>
   </WsMortProdContainerv02>
</allMortProdContainers>'''

println XML.toJSONObject(xml).toString(2)

来源：https://stackoverflow.com/questions/50838938/groovy-xml-to-json-without-knowing-each-key

标签

json

xml

groovy

soapui

ready-api