问题
Question is similar to: How can I check that two objects have the same set of property names? but only one difference
I want to check:
var objOne = {"a":"one","b":"two","c":{"f":"three_one"}};
var objTwo = {"a":"four","b":"five","c":{"f":"six_one"}};
have the same set of keys in all level?
For example deepCheckObjKeys(objOne, objTwo)
would return true
where deepCheckObjKeys(objOne, objThree)
return false
, if:
var objThree = {"a":"four","b":"five","c":{"g":"six_one"}};
Since objThree.a.c.f
is undefined
in objThree.
A function like this:
'use strict';
function objectsHaveSameKeys() {
for (var _len = arguments.length, objects = Array(_len), _key = 0; _key < _len; _key++) {
objects[_key] = arguments[_key];
}
var allKeys = objects.reduce(function (keys, object) {
return keys.concat(Object.keys(object));
}, []);
var union = new Set(allKeys);
return objects.every(function (object) {
return union.size === Object.keys(object).length;
});
}
only checks the first level.
PS: objectsHaveSameKeys() ES6 equivalent:
function objectsHaveSameKeys(...objects):boolean {
const allKeys = objects.reduce((keys, object) => keys.concat(Object.keys(object)), []);
const union = new Set(allKeys);
return objects.every(object => union.size === Object.keys(object).length);
}
回答1:
I'd just do a recursive check if a property's value is an object; see comments:
const deepSameKeys = (o1, o2) => {
// Get the keys of each object
const o1keys = Object.keys(o1).sort();
const o2keys = Object.keys(o2).sort();
// Make sure they match
// If you don't want a string check, you could do
// if (o1keys.length !== o2keys.length || !o1keys.every((key, index) => o2keys[index] === key)) {
if (o1keys.join() !== o2keys.join()) {
// This level doesn't have the same keys
return false;
}
// Check any objects
return o1keys.every(key => {
const v1 = o1[key];
const v2 = o2[key];
if (v1 === null) {
return v2 === null;
}
const t1 = typeof v1;
const t2 = typeof v2;
if (t1 !== t2) {
return false;
}
return t1 === "object" ? deepSameKeys(v1, v2) : true;
});
};
var objOne = {"a":"one","b":"two","c":{"f":"three_one"}};
var objTwo = {"a":"four","b":"five","c":{"f":"six_one"}};
var objThree = {"a":"four","b":"five","c":{"g":"six_one"}};
console.log("objOne, objTwo: " + deepSameKeys(objOne, objTwo));
console.log("objTwo, objThree: " + deepSameKeys(objTwo, objThree));
回答2:
You can create recursive function that will return all keys and check if they are equal with every()
.
var objOne = {"a":"one","b":"two","c":{"f":"three_one"}};
var objTwo = {"a":"four","b":"five","c":{"f":"six_one"}};
function checkKeys(obj1, obj2) {
function inner(obj) {
var result = []
function rec(obj, c) {
Object.keys(obj).forEach(function(e) {
if (typeof obj[e] == 'object') rec(obj[e], c + e)
result.push(c + e)
})
}
rec(obj, '')
return result
}
var keys1 = inner(obj1), keys2 = inner(obj2)
return keys1.every(e => keys2.includes(e) && keys1.length == keys2.length)
}
console.log(checkKeys(objOne, objTwo))
来源:https://stackoverflow.com/questions/41802259/javascript-deep-check-objects-have-same-keys