PHP instanceof returns false for true condition

问题

I'm thoroughly confused as to why php's instanceof operator insists that the LVALUE here is not an instance of the defined class when get_class says that it is.

class WhereIn {
    public function __construct($args) {
        echo "is instanceof: " . ($args[0] instanceof ActiveRecordField) . EOL;
        echo "get class: " . get_class($args[0]) . EOL;
    }
}

The output from this method is:

is instanceof: 
get class: ActiveRecordField

For reference, I'm using PHP 5.6.9.

回答1:

If you use namespaces in your code, you need to provide it directly:

if ($args[0] instanceof ActiveRecordField) // False

if ($args[0] instanceof \MyCompany\Classes\ActiveRecordField) // True

来源：https://stackoverflow.com/questions/30278401/php-instanceof-returns-false-for-true-condition