C Basic Head Command | 易学教程

问题

I'm trying to recreate the head, and tail commands from linux for my programming class. We just started using C so I'm new to the idea of allocating memory and pointers. I'm wondering why this doesn't work.

#include <stdio.h>
#include <stdlib.h>

int main(int argc,char **argv){

    /* Checks if correct amount of arguements */

    if(argc != 2 || argc != 4){
        printf("Usage: %s head <file> \n Or: head <file> -n <number of characters>", argv[0]);
        exit(-1);
    }

    if(strcmp(argv[1], "-n" != 0)){
        char fileName[strlen(argv[1])] = argv[1];
    }
}

//Compile error on char fileName[strlen(argv[1])] = argv[1];

Any additional insight would also be helpful.

回答1:

First things first, your usage doesn't match your argument checking. According to the usage, you must use one of:

head <filename>
head <filename> -n <count>

In other words, argv[1] is always the filename, argv[2] is the one that needs to be set to -n if there are more than two arguments.

Secondly, unless you want to use VLAs (variable length arrays), you should probably just set up a pointer to the filename argument with something like:

char *fileName = argv[1];

You don't need to change it at all (you'll just be passing it to fopen, presumably), so it's a waste trying to make another copy.

In addition, your if statement is wrong as an or, it should be an and. It's guaranteed that argc will either not be 2 or not be 4, since it can't be both at the same time.

I would start with something like:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

static int usage (void) {
    printf ("Usage: head <file>\n");
    printf ("   or: head <file> -n <number of characters>\n");
    return -1;
}

int main (int argc,char *argv[]) {
    char *fileName;
    int lineCount;

    // Checks if correct arguments

    if ((argc != 2) && (argc != 4)) return usage();

    if ((argc == 4) && (strcmp(argv[2], "-n" != 0)) return usage();

    // Get file spec and line count

    fileName = argv[1];

    lineCount = (argc == 2) ? 10 : atoi (argv[3]); // or strtol for purists
    if (linecount < 0) lineCount = 0;

    // Now go ahead and implement the logic for head.

}

回答2:

I think it's better to write:

char fileName[strlen(argv[1])+1];
strcpy(fileName, argv[1]);

or (if you don't whant to make a copy of string) :

char* fileName = argv[1];

来源：https://stackoverflow.com/questions/12361558/c-basic-head-command

标签

Linux

tail

head