问题
I have been struggling the last days trying to compute the degrees of freedom of two pair of vectors (x and y) following reference of Chelton (1983) which is:
degrees of freedom according to Chelton(1983)
and I can't find a proper way to calculate the normalized cross correlation function using np.correlate, I always get an output that it isn't in between -1, 1.
Is there any easy way to get the cross correlation function normalized in order to compute the degrees of freedom of two vectors?
回答1:
Nice Question. There is no direct way but you can "normalize" the input vectors before using np.correlate
like this and reasonable values will be returned within a range of [-1,1]:
Here i define the correlation as generally defined in signal processing textbooks.
c'_{ab}[k] = sum_n a[n] conj(b[n+k])
CODE: If a and b are the vectors:
a = (a - np.mean(a)) / (np.std(a) * len(a))
b = (b - np.mean(b)) / (np.std(b))
c = np.correlate(a, b, 'full')
References:
https://docs.scipy.org/doc/numpy/reference/generated/numpy.correlate.html
https://en.wikipedia.org/wiki/Cross-correlation
回答2:
a = np.dot(abs(var1),abs(var2),'full')
b = np.correlate(var1,var2,'full')
c = b/a
This is my idea: but it will normalize it 0-1
来源:https://stackoverflow.com/questions/53436231/normalized-cross-correlation-in-python