MVC3 dropdownlistfor

僤鯓⒐⒋嵵緔 提交于 2019-12-22 08:59:12

问题


I would like to make a dropdown list, with the numbers 0-10. So users can rate something. At the moment, I have a label: @Html.LabelFor(model=> model.RATE) How can I modify this code that I will have a dropdown box? And that the value of the dropdown box will be stored in model.RATE?

The label is working, but it would be much better to have a dropdown menu.

SOLUTION:

@Html.DropDownListFor(model => model.RATE, Enumerable.Range(0,11).Select( x => new SelectListItem { Text = x.ToString() }));

回答1:


Just create a list of SelectListItem objects that contain the ratings, and then use Html.DropDownListFor with the rating stored in your model (Model.RATE).

@{
    var ratings = new List<SelectListItem>();
    for( var i = 0; i <= 10; i++ ) {
        days.Add( new SelectListItem { Text = i.ToString(), Value = i.ToString(), Selected = Model.RATE == i } );
    }
}
@Html.DropDownListFor( x => x.RATE, ratings )



回答2:


@Html.DropDownListFor(model => model.RATE, new SelectList(Enumerable.Range(0, 11)))

This will do the data binding to the form and from the form




回答3:


@Html.DropDownListFor(m => m.RATE, Model.RateSelectList, "<- Select Option ->")

Model.RateSelectList would be of type IEnumerable<SelectListItem>, m.RATE would be your nullable integer(int?) property. The third parameter would be your default text that would show if m.RATE is null.



来源:https://stackoverflow.com/questions/10709588/mvc3-dropdownlistfor

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