问题
I have a following problem in c# SDK: when I try to run multiquery in my desktop application with following string (searching for pairs of IDs of mutual friends) I get a parser error:
string strCommonFriendsQuery = "{
\"user_friends\":\"SELECT uid2 FROM friend WHERE uid1 = me()\",
\"mutual_friends\":\"SELECT uid1, uid2 FROM friend WHERE uid1 IN (SELECT uid2 FROM #user_friends) AND uid2 IN (SELECT uid2 FROM #user_friends)\"
}";
fb.Query(strCommonFriendsQuery);
Parser error: unexpected '{' at position 0.
The same string (without the escape sequences before quotation marks) works if I paste it to http://developers.facebook.com/docs/reference/rest/fql.multiquery/ but not in http://developers.facebook.com/docs/reference/rest/fql.query/ so the problem is that I need to launch it as multiquery and not as a query - now what I would like to ask is:
Is it possible to somehow process multi-query using the Facebook.FacebookClient.Query function of the SDK or do I have to write a function which would do that? As I understand the only thing I would need to change is the address to which it connects to. If so, could it be added in the next SDK version?
回答1:
To do a multiquery with a reference to the first query, such as the one in the question, do as follows:
//note: queries begin from 0, not from 1
string query0 = "SELECT uid2 FROM friend WHERE uid1 = me()";
string query1 = "SELECT uid1, uid2 FROM friend WHERE uid1 IN (SELECT uid2 FROM #query0) AND uid2 IN (SELECT uid2 FROM #query0)";
dynamic result = fb.Query(query0, query1);
To answer this, I got inspired from here (had to figure out that queries start from 0): How to use fql.multiquery with C# SDK
Enjoy!
回答2:
Here is an alternate to firepol's answer, with named queries:
var queries =
new Dictionary<string, object>
{
{ "FamDamly", "select uid from family where profile_id = me()" },
{ "FamDetails", "select uid, first_name from user where uid in #FamDamly" }
};
client.Get(queries);
来源:https://stackoverflow.com/questions/5144488/starting-multiquery-in-client-throws-parser-error