Guzzle get file and forward it

问题

I have a web-service that gets a file and returns it to the user (based on Symfony). Ever since I used curl to do this.

I just found guzzlehttp and it seems great. However, I do not know how to do this with guzzle without saving the downloaded file (xml or txt) to a local file, read it from the file system a returning it to the user. I want to do this without saving to the file system.

回答1:

public function streamAction()
{
     $response = $client->request(
        'GET', 'http://httpbin.org/stream-bytes/1024', ['stream' => true]
     );

     $body = $response->getBody();

     $response = new StreamedResponse(function() use ($body) {
         while (!$body->eof()) {
             echo $body->read(1024);
         }
     });

     $response->headers->set('Content-Type', 'text/xml');

     return $response;
}

来源：https://stackoverflow.com/questions/36771849/guzzle-get-file-and-forward-it