What is the inverse of regularization strength in Logistic Regression? How should it affect my code?

问题

I am using sklearn.linear_model.LogisticRegression in scikit learn to run a Logistic Regression.

C : float, optional (default=1.0) Inverse of regularization strength;
    must be a positive float. Like in support vector machines, smaller
    values specify stronger regularization.

What does C mean here in simple terms please? What is regularization strength?

回答1:

Regularization is applying a penalty to increasing the magnitude of parameter values in order to reduce overfitting. When you train a model such as a logistic regression model, you are choosing parameters that give you the best fit to the data. This means minimizing the error between what the model predicts for your dependent variable given your data compared to what your dependent variable actually is.

The problem comes when you have a lot of parameters (a lot of independent variables) but not too much data. In this case, the model will often tailor the parameter values to idiosyncrasies in your data -- which means it fits your data almost perfectly. However because those idiosyncrasies don't appear in future data you see, your model predicts poorly.

To solve this, as well as minimizing the error as already discussed, you add to what is minimized and also minimize a function that penalizes large values of the parameters. Most often the function is λΣθ_j², which is some constant λ times the sum of the squared parameter values θ_j². The larger λ is the less likely it is that the parameters will be increased in magnitude simply to adjust for small perturbations in the data. In your case however, rather than specifying λ, you specify C=1/λ.

来源：https://stackoverflow.com/questions/22851316/what-is-the-inverse-of-regularization-strength-in-logistic-regression-how-shoul