问题
Possible Duplicate:
create unique profile page for each user python
I am using google appengine with python and jinja2 and trying to give each user in my app a unique URL to their profile page that can be visited by anyone without logging in. Here is my code thus far:
class ProfilePage(webapp2.RequestHandler):
def get(self, profile_id):
user = User.get_by_id(profile_id)
#profile_id = some unique field
if user:
#Get all posts for that user and render....
theid = user.theid
personalposts = db.GqlQuery("select * from Post where theid =:1 order by created desc limit 30", theid)
else:
personalposts = None
global visits
logout = users.create_logout_url(self.request.uri)
currentuser = users.get_current_user()
self.render('profile.html', user = currentuser, visits = visits, logout=logout, personalposts=personalposts)
app = webapp2.WSGIApplication([('/', MainPage),
('/profile/([0-9]+)', ProfilePage),])
When I try and test it it just gives me a 404 error. I suppose if the code is right I might be using the wrong testing URL. For example if this is their OpenID ID: How can I test it out I tried just entering www.url.com/profile/https://www.google.com/accounts/o8/id?id=AItOawlILoSKGNwU5RuTiRtXug1l8raLE45g-56 would just the id="this part" be what I put so I would have:
url = www.url.com/profile/AItOawlILoSKGNwU5RuTiRtXug1l8raLE45g-56
That's what I tried and it didn't quite work. Thanks in advance for the help!
回答1:
Try this regular expression:
r'^/profile/\w*?-(\d+)$'
Though I also must tell you that this is a very bad idea!
回答2:
The url that your are using (www.url.com/profile/AItOawlILoSKGNwU5RuTiRtXug1l8raLE45g-56) the last part of the url is a full key to the entity while in the code your are using the entity id to load it (using get_by_id() ).
来源：https://stackoverflow.com/questions/11256738/create-permenant-unique-links-based-on-a-user-id